NSString比较特殊字符独立

Question

如何比较两个字符独立的NSString ?

NSPredicate提供==[d]比较器。
然而，我没有找到一种方法来直接比较两个NSString。

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例如，这两个字符串应该被认为是相同的:

Š充足Š特林

样本字符串

Answer 1

NSString *s1 = @"Šämplé Štrïñg";
NSString *s2 = @"Sample String";
NSComparisonResult cmp = [s1 compare:s2 options:NSDiacriticInsensitiveSearch];
// --> cmp = NSOrderedSame

Answer 2

使用compare:options::

NSString *str1 = ...;
NSString *str2 = ...;
NSComparisonResult result = [str1 compare:str2 options:NSDiacriticInsensitiveSearch | NSCaseInsensitiveSearch | NSWidthInsensitiveSearch];

如果您想对字符串执行其他操作，您可以将这两个字符串折叠成更简单的形式:

NSString *fold1 = [str1 stringByFoldingWithOptions:NSDiacriticInsensitiveSearch | NSCaseInsensitiveSearch | NSWidthInsensitiveSearch locale:[NSLocale currentLocale]];
NSString *fold2 = [str2 stringByFoldingWithOptions:NSDiacriticInsensitiveSearch | NSCaseInsensitiveSearch | NSWidthInsensitiveSearch locale:[NSLocale currentLocale]];
NSRange range = [fold1 rangeOfString:fold2]; // or other string comparisons