我正在制作一个C++读心器程序，它即将完成。但是，它觉得有必要跳过第二个cin。我已经搜索过了，但我不确定出了什么问题。我已经检查了代码，我敢打赌我做了一些愚蠢的事情，但我仍然对此感到困惑。跳过的 cin 在第 32 行，这是我的代码：
#include <iostream>
#include <string>
#include <cstdlib>
using namespace std;
int main()
{
//declaring variables to be used later
string name;
string country;
int age;
//header goes below
cout << " @@@@@@@@@@@@-MIND READER-@@@@@@@@@@@@nn";
//asks if the user would like to continue and in not, terminates
cout << "Would like you to have your mind read? Enter y for yes and n for no." << endl;
cout << "If you do not choose to proceed, this program will terminate." << endl;
string exitOrNot;
//receives user's input
cin >> exitOrNot;
//deals with input if it is 'y'
if (exitOrNot == "y"){
cout << "Okay, first you will need to sync your mind with this program. You will have to answer the following questions to synchronise.nn";
//asks questions
cout << "Firstly, please enter your full name, with correct capitalisation:nn";
cin >> name;
cout << "Now please enter the country you are in at the moment:nn";
cin >> country; //<------ Line 32
cout << "This will be the final question; please provide your age:nn";
cin >> age;
//asks the user to start the sync
cout << "There is enough information to start synchronisation. Enter p to start the sync...nn";
string proceed;
cin >> proceed;
//checks to see if to proceed and does so
if (proceed == "p"){
//provides results of mind read
cout << "Sync complete." << endl;
cout << "Your mind has been synced and read.nn";
cout << "However, due to too much interference, only limited data was aquired from your mind." << endl;
cout << "Here is what was read from your mind:nn";
//puts variables in sentence
cout << "Your name is " << name << " and you are " << age << " years old. You are based in " << country << "." << endl << "nn";
cout << "Thanks for using Mind Reader, have a nice day. Enter e to exit." << endl;
//terminates the program the program
string terminate;
cin >> terminate;
if (terminate == "e"){
exit(0);
}
}
}
//terminates the program if the input is 'n'
if (exitOrNot == "n"){
exit(0);
}
return 0;
}
编辑：这是我运行它时发生的情况：
@@@@@@@@@@@@-MIND READER-@@@@@@@@@@@@
Would like you to have your mind read? Enter y for yes and n for no.
If you do not choose to proceed, this program will terminate.
y
Okay, first you will need to sync your mind with this program. You will have to
answer the following questions to synchronise.
Firstly, please enter your full name, with correct capitalisation:
John Smith
Now please enter the country you are in at the moment:
This will be the final question; please provide your age:
13
There is enough information to start synchronisation. Enter p to start the sync.
..
p
Sync complete.
Your mind has been synced and read.
However, due to too much interference, only limited data was aquired from your m
ind.
Here is what was read from your mind:
Your name is John and you are 13 years old. You are based in Smith.
Thanks for using Mind Reader, have a nice day. Enter e to exit.
e
Process returned 0 (0x0) execution time : 78.220 s
Press any key to continue.
这里有一个截图，让它更清楚：http://puu.sh/4QZb3.png我无法将其附加到这篇文章中，因为我没有足够的代表。
还值得注意的是它如何使用用户的姓氏作为国家/地区。我相信问题与输入不是整数有关。
谢谢。
您只能在cin中输入一个单词。相反，请使用 getline(cin, string name); 如果仍然不起作用，请在getline(cin, string name);之前添加一个cin.ignore();，如下所示：
string country;
cout << "Now please enter the country you are in at the moment:nn";
cin.ignore();
getline(cin, country);
这现在肯定会起作用。
问题是你使用的是： cin >>从用户那里获取字符串。如果用户输入超过 1 个单词，则会导致代码中的行相互跳过。为了解决这个问题，我们将使用： getLine(cin,yourStringHere) 从用户那里获取字符串。这是您的代码全部修复：
#include <iostream>
#include <string>
#include <cstdlib>
using namespace std;
int main()
{
string name;
string country;
int age;
cout << " @@@@@@@@@@@@-MIND READER-@@@@@@@@@@@@nn";
cout << "Would like you to have your mind read? Enter y for yes and n for no." << endl;
cout << "If you do not choose to proceed, this program will terminate." << endl;
string exitOrNot;
getline (cin,exitOrNot); /*<-----Changed from cin to getLine*/
if (exitOrNot == "y"){
cout << "Okay, first you will need to sync your mind with this program. You will have to answer the following questions to synchronise.nn";
cout << "Firstly, please enter your full name, with correct capitalisation:nn";
getline(cin,name); /*<--Another string*/
cout << "Now please enter the country you are in at the moment:nn";
getline(cin,country); /*<--Another string*/
cout << "This will be the final question; please provide your age:nn";
cin >> age;
cout << "There is enough information to start synchronisation. Enter p to start the sync...nn";
string proceed;
cin >> proceed;
if (proceed == "p"){
cout << "Sync complete." << endl;
cout << "Your mind has been synced and read.nn";
cout << "However, due to too much interference, only limited data was aquired from your mind." << endl;
cout << "Here is what was read from your mind:nn";
cout << "Your name is " << name << " and you are " << age << " years old. You are based in " << country << "." << endl << "nn";
cout << "Thanks for using Mind Reader, have a nice day. Enter e to exit." << endl;
string terminate;
cin >> terminate;
if (terminate == "e"){
exit(0);
}
}
}
if (exitOrNot == "n"){
exit(0);
}
return 0;
}
上述用户所说的，cin 只允许在每个 cin 的字符串中输入 1 个单词。因此，我认为您想要的是：getline（cin，名称）
cin.get();
cout << "Now please enter the country you are in at the moment:nn";
cin >> country; //<------ Line 32
在 cout 之前键入 cin.get（），就像我上面所做的那样，您的问题将得到解决。