我正在输入文件,对其进行解析,将信息存储在对象中,然后将对象推入数组。对象的值之一是'sequence':[]名称价值对。一旦我将DNA序列存储到"序列"的值中,我想加入所有元素。但是,我尝试使用.join()无济于事。以下是我的代码:
// Check for the various File API support.
if (window.File && window.FileReader && window.FileList && window.Blob) {
// Great success! All the File APIs are supported.
} else {
alert('The File APIs are not fully supported in this browser.');
}
var objArray = [];
var obj;
function parse(event) {
//Get the file from HTML input tag
var file = event.target.files[0];
if(file) {
//Create a new file reader
var reader = new FileReader();
//When the file reader loads
reader.onload = function(evt) {
//Add the contents of file to variable contents
var contentsByLine = evt.target.result.split('n');
//Alert user the file upload has succeeded
console.log('File ' + file.name + ' was successfully loaded.');
for(var i in contentsByLine){
if(contentsByLine[i][0] == '>'){
obj = {
id: contentsByLine[i],
sequence: [],
lead_trim: 0,
trail_trim: 0
};
objArray.push(obj);
}else{
obj.sequence.push(contentsByLine[i]);
}
// console.log(objArray[i]['sequence']);
}
console.log(objArray)
// Create the DataView.
var dataView = new Slick.Data.DataView();
// Pass it as a data provider to SlickGrid.
var grid = new Slick.Grid("#table", dataView, columns, options);
// Make the grid respond to DataView change events.
dataView.onRowCountChanged.subscribe(function (e, args) {
grid.updateRowCount();
grid.render();
});
dataView.onRowsChanged.subscribe(function (e, args) {
grid.invalidateRows(args.rows);
grid.render();
});
var data = [];
for (var i in objArray){
objArray[i]['sequence'].join();
data.push(objArray[i]);
}
dataView.setItems(data);
dataView.getItems();
//console.log(data);
}
reader.readAsText(file);
} else {
alert('Failed to upload file!');
}
}
document.getElementById('fileItem').addEventListener('change', parse, false);
您使用的连接不正确。加入返回值。您需要将其设置为某物。
for (var i in objArray){
objArray[i]['sequence'].join();
data.push(objArray[i]);
}
应该是:
for (var i = 0; i < objArray.length; i++){
objArray[i]['sequenceString'] = objArray[i]['sequence'].join();
data.push(objArray[i]);
}
您需要将结果存储在变量中:
var result = objArray[i]['sequence'].join();
data.push(result);
短:
data.push( objArray[i]['sequence'].join() );