如何在使用 JAXB 注释时解包 JSON 的根目录



我使用 JAXB 注解来使用 Spring 序列化/反序列化对象。

这是我的响应类:

@XmlRootElement(name = "animals")
public class PetClinic implements Serializable {
    @XmlElementWrapper(name = "animals")
    @XmlElement(name = "animal")
    private Collection<Animal> animals;
    public Collection<Animal> getAnimals() {
        return animals;
    }
    public void setAnimalsCollection<Animal> animals) {
        this.animals = animals;
    }
}

我想得到这样的 JSON

{
    "animals": [
        {...}, 
        {...}
    ]
}

我试图解开根元素的包装,但我的所有解决方案都不起作用:

1)我尝试在字段中使用@JsonUnwrapped注释

2)我尝试使用@JsonSerialize

@JsonSerialize(using = PetClinicSerializer.class)

序列化程序代码:

ObjectMapper mapper = new ObjectMapper();
@Override
public void serialize(PetClinic clinic, JsonGenerator generator, SerializerProvider serializerProvider) throws IOException, JsonProcessingException {
    mapper.configure(SerializationFeature.WRAP_ROOT_VALUE, false);
    String clinicAsString = mapper.writeValueAsString(clinic);
    generator.writeString(clinicAsString);
}

如何获取上面提到的 JSON?

我只是在没有任何jaxb表示法的情况下使用了ObjectMapper并得到了想要的结果:

import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.databind.SerializationFeature;
import java.io.Serializable;
import java.util.Arrays;
import java.util.Collection;
public class PetClinic implements Serializable {
    private Collection<Animal> animals;
    public Collection<Animal> getAnimals() {
        return animals;
    }
    public void setAnimals(Collection<Animal> animals) {
        this.animals = animals;
    }
    public static void main(String[] args) throws Exception {
        PetClinic pc = new PetClinic();
        Animal cat = new Animal();
        cat.setName("cat");
        Animal dog = new Animal();
        dog.setName("dog");
        pc.setAnimals(Arrays.asList(cat, dog));
        ObjectMapper mapper = new ObjectMapper();
        mapper.enable(SerializationFeature.INDENT_OUTPUT);
        String s = mapper.writeValueAsString(pc);
        System.out.println(s);
    }
}
class Animal {
    private String name;
    public String getName() {
        return name;
    }
    public void setName(String name) {
        this.name = name;
    }
}

输出

{
  "animals" : [ {
    "name" : "cat"
  }, {
    "name" : "dog"
  } ]
}

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