将链接值传递给bean

Question

我有一个JSP文件，其中包含如下链接：

<a href="links.do?method=homeAdmin">
<a href="links.do?method=signUp">

我有一个动作类LinkAction.java:

public class LinkAction extends org.apache.struts.action.Action {
    public ActionForward signUp(ActionMapping mapping, ActionForm form,
            HttpServletRequest request, HttpServletResponse response)
            throws Exception {
        return mapping.findForward("signUp");
    }
    public ActionForward homeAdmin(ActionMapping mapping, ActionForm form,
            HttpServletRequest request, HttpServletResponse response)
            throws Exception {
        return mapping.findForward("homeAdmin");
    }
}

问题是它不起作用。但当我将其更改为类似的内容时，它只适用于signUp操作。

public class LinkAction extends org.apache.struts.action.Action {
    @Override
    public ActionForward execute(ActionMapping mapping, ActionForm form,
            HttpServletRequest request, HttpServletResponse response)
            throws Exception {
        return mapping.findForward("signUp");
    }
}

我还试着把它改成

public class LinkAction extends DispatchAction { ... }

这是我的struts-config.xml

<action input="/index.jsp"
        name="signUp" 
        path="/links" 
        scope="session" 
        type="Actions.LinkAction">
   <forward name="signUp" path="/signUp.jsp"/>
   <forward name="homeAdmin" path="/homeAdmin.jsp"/>
</action>

我想将这个单一操作文件用于我的网页中的所有链接。我该怎么做？

Answer 1

您需要添加parameter="method"。这标识了包含方法名称的请求参数。

如果你有下一个行动类：

package actions;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.apache.struts.action.ActionForm;
import org.apache.struts.action.ActionForward;
import org.apache.struts.action.ActionMapping;
import org.apache.struts.actions.DispatchAction;
public class LinkAction extends DispatchAction {
    public ActionForward signUp(ActionMapping mapping, ActionForm form,
            HttpServletRequest request, HttpServletResponse response)
            throws Exception {
        return mapping.findForward("signUp");
    }
    public ActionForward homeAdmin(ActionMapping mapping, ActionForm form,
            HttpServletRequest request, HttpServletResponse response)
            throws Exception {
        return mapping.findForward("homeAdmin");
    }
}

您需要在struts-config.xml文件中进行以下配置：

<form-beans>
    <form-bean name="SignUpForm" type="org.apache.struts.action.DynaActionForm">
        <form-property name="fname" type="java.lang.String" />
        <form-property name="lname" type="java.lang.String" />
        <form-property name="usr" type="java.lang.String" />
        <form-property name="pwd" type="java.lang.String" />
    </form-bean>
</form-beans>
<action-mappings>
    <action path="/links"
            type="actions.LinkAction"
            name="SignUpForm"
            input="/index.jsp"
            parameter="method"
            scope="session">
       <forward name="signUp" path="/signUp.jsp"/>
       <forward name="homeAdmin" path="/homeAdmin.jsp"/>
    </action>
</action-mappings>

另请参见org.apache.struts.actions.DispatchAction。

Answer 2

Struts1 always calls execute(ActionMapping mapping, ActionForm form,
        HttpServletRequest request, HttpServletResponse response) 

用于处理请求的方法。您可以尝试在execute()方法中获取请求parameter('method')，并根据其值将其代理到homeAdmin或signUp。

Answer 3

正如piyush上面解释的那样，使用DispatchAction点击扩展操作类http://struts.apache.org/release/1.3.x/struts-extras/apidocs/org/apache/struts/actions/DispatchAction.html

配置文件中的配置应该类似于

<action-mappings>
  <action input="/yourpage.jsp" parameter="method" name="yourform" 
    path="/yourAction" scope="session/request" type="yourpackage.youraction">
    <forward name="signup" path="/yourpage.jsp" />
</action>

Answer 4

据我所知，

1.）有没有办法，通过一个动作类，你可以处理多个任务，比如：你的两个方法都可以工作。

public ActionForward signUp(ActionMapping mapping, ActionForm form,
    HttpServletRequest request, HttpServletResponse response)
    throws Exception {
return mapping.findForward("signUp");
}
public ActionForward homeAdmin(ActionMapping mapping, ActionForm form,
    HttpServletRequest request, HttpServletResponse response)
    throws Exception {
return mapping.findForward("homeAdmin");
}

如果它是正确的，那么您应该选择另一种类型的Action，即DispatchAction，因为它提供了编写多个方法的能力。

详细信息：

public class LanguageSelectAction extends DispatchAction{
public ActionForward chinese(ActionMapping mapping,ActionForm form,
    HttpServletRequest request,HttpServletResponse response) 
throws Exception {
    request.getSession().setAttribute(
            Globals.LOCALE_KEY, Locale.SIMPLIFIED_CHINESE);
    return mapping.findForward("provide");
}
public ActionForward english(ActionMapping mapping,ActionForm form,
    HttpServletRequest request,HttpServletResponse response) 
throws Exception {
    request.getSession().setAttribute(
            Globals.LOCALE_KEY, Locale.ENGLISH);
    return mapping.findForward("success");
}
public ActionForward german(ActionMapping mapping,ActionForm form,
    HttpServletRequest request,HttpServletResponse response) 
throws Exception {
    request.getSession().setAttribute(
            Globals.LOCALE_KEY, Locale.GERMAN);
    return mapping.findForward("success");
}
public ActionForward france(ActionMapping mapping,ActionForm form,
    HttpServletRequest request,HttpServletResponse response) 
throws Exception {
    request.getSession().setAttribute(
            Globals.LOCALE_KEY, Locale.FRANCE);
    return mapping.findForward("success");
}

}

您可以在此处获得详细的