对单个表的日期、整数和字符串数据类型字段执行多列搜索


我正在工作 Spring Data - 多列搜索和

Spring Data Jpa - 类型Specification已被弃用,我想搜索多个列,如Date(Java 8 LocalDateTimeInstantLocalDate等(,IntegerString数据类型。

但根据我的代码,只考虑String字段(根据where子句中的日志(:

select
    employee0_.employee_id as employee1_0_,
    employee0_.birth_date as birth_da2_0_,
    employee0_.email_id as email_id3_0_,
    employee0_.first_name as first_na4_0_,
    employee0_.last_name as last_nam5_0_,
    employee0_.project_association as project_6_0_,
    employee0_.status as status7_0_ 
from
    employee employee0_ 
where
    employee0_.first_name like ? 
    or employee0_.email_id like ? 
    or employee0_.status like ? 
    or employee0_.last_name like ?

下面是我开发的代码。

员工.java

@Builder
@Data
@AllArgsConstructor
@NoArgsConstructor
@Entity
public class Employee implements Serializable{
    private static final long serialVersionUID = 1L;
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name="EMPLOYEE_ID")
    private Long employeeId;
    @Column(name="FIRST_NAME")
    private String firstName;
    @Column(name="LAST_NAME")
    private String lastName;
    @Column(name="EMAIL_ID")
    private String email;
    @Column(name="STATUS")
    private String status;
    @Column(name="BIRTH_DATE")
    private LocalDate birthDate;
    @Column(name="PROJECT_ASSOCIATION")
    private Integer projectAssociation;
}

注意:用户可以使用全局搜索搜索任何值,无论用户搜索什么,都应该能够看到数据,而不考虑数据类型。

员工规范.java

public class EmployeeSpecification {
    public static Specification<Employee> textInAllColumns(String text, List<String> attributes) {
        if (!text.contains("%")) {
            text = "%" + text + "%";
        }
        final String finalText = text;
        return (root, query, builder) -> builder
                .or(root.getModel().getDeclaredSingularAttributes().stream().filter(a -> {
                    if (a.getJavaType().getSimpleName().equalsIgnoreCase("String")) {
                        return true;
                    }else if(a.getJavaType().getSimpleName().equalsIgnoreCase("date")) {
                        return true;
                    }
                    else {
                        return false;
                    }
                }).map(a -> builder.like(root.get(a.getName()), finalText)).toArray(Predicate[]::new));
    }
}

但这种方法只考虑字符串字段,而不考虑日期和整数数据类型。我们该怎么做?

更改:

if(a.getJavaType().getSimpleName().equalsIgnoreCase("date")) 

自:

if(a.getJavaType().getSimpleName().equalsIgnoreCase("LocalDate"))

分析问题,我给你一个更灵活的解决方案,这段代码解决了你的问题,并允许即时生成动态查询。这个想法是使用任何类型对象进行查询。

首先,创建此类以保存查询的参数

@RequiredArgsConstructor
public class Search {
    @Getter
    @NonNull private String field;
    @Getter
    @NonNull private String operator;
    @Getter
    @NonNull private Object value;
}

然后根据以下代码为每个对象构建规范

public static Specification<Employee> searchFreeAttrsEmployee(List<Search> attributes) {
    return new Specification<Employee>() {
        private static final long serialVersionUID = 4817323527595445596L;
        public Predicate toPredicate(Root<Employee> root, CriteriaQuery<?> query, CriteriaBuilder builder) {
            List<Predicate> r=new ArrayList<Predicate>(); 
            attributes.stream().forEach(t -> {
                r.add(setParams(t, root, builder));
            });
            Predicate list[] = new Predicate[r.size()];
            r.toArray(list);
            return builder.or(list);
        }
    };
}
public static Predicate setParams(Search t, Root<?> root, CriteriaBuilder builder) {
    if (t.getOperator().equals("like")) {
        return builder.like(root.get(t.getField()), t.getValue().toString());
    }
    if (t.getOperator().equals("equal")) {
        return builder.equal(root.get(t.getField()), t.getValue().toString());
    }       
    if (t.getOperator().equals("gtInt")) {
        return builder.gt(root.get(t.getField()), Integer.valueOf(t.getValue().toString()));
    }       
    if (t.getOperator().equals("eqInt")) {
        return builder.equal(root.get(t.getField()), Integer.valueOf(t.getValue().toString()));
    }       
    return null;
}

}

以这种方式运行搜索

    List<Search> l=new ArrayList<Search>();
    l.add(new Search("firstName","like","Peter"));
    List<Employee> list = pe.findAll(Specifications.searchFreeAttrsEmployee(l));

您可以聚合许多属性来进行搜索。我希望这段代码会很有用。

问候

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