匹配单词模式，并在 R 中将单词替换为 NA

Question

我在R中有2个数据帧 - 一个名称列表，另一个是单词字典。如果名称的任何部分是单词字典的一部分，则替换为NA，否则返回名称

名称 - 数据帧

Name
Louis
Messi
duplessis
Jegan
Praveen

单词字典 - 数据帧

Dictionary
vee
sis

预期输出

Name        Processed_Name
Louis       Louis
Messi       Messi
duplessis   NA
Jegan       Jegan
Praveen     NA

Answer 1

library(data.table) # needed library
# create data
dt <- data.table("Name"=c("Louis",
                          "Messi",
                          "duplessis",
                          "Jegan",
                          "Praveen"))
dict <- c("vee","sis")
# make a combined vector of the words in the dictionary
dict_2 <- paste0(dict,collapse = "|") 
# desired output
dt[,processed_Name:=ifelse(Name%like%dict_2,NA,Name)]

输出

        Name processed_Name
1:     Louis          Louis
2:     Messi          Messi
3: duplessis             NA
4:     Jegan          Jegan
5:   Praveen             NA

根据OP的评论进行更新

  # changed the input a bit, so that it contains the numbers 
# that i am going to generate for the dictionary.
dt <- data.table("Name"=c("Loui1s",
                          "Messi",
                          "duple2ssis",
                          "Jegan",
                          "Praveen"))
dict_all <- as.character(c(1:5000)) # i generate numbers so that they all are different
dict_split <- split(dict_all, ceiling(seq_along(dict_all)/1000))
dict_split_2 <- lapply(dict_split, function(x){paste0(x, collapse = "|")})
dt[,processed_Name_2:=ifelse(Name%like%dict_split_2[[1]] | Name%like%dict_split_2[[2]] |
                               Name%like%dict_split_2[[3]] | Name%like%dict_split_2[[4]] |
                               Name%like%dict_split_2[[5]],NA,Name)]