我有一个包含fromJson方法的对象。 此方法不起作用,因为无法访问类的私有属性? 出了什么问题,如何处理?代码是用打字稿编写的。
class Example {
private Foo: string; // does not matter if private or public, same effect, and normaly has to be private
constructor(input?: string) {
if (!!input) {
this.foo = input;
}
}
set foo(value: string) {
this.Foo = value;
}
get foo(): string {
return this.Foo;
}
public static fromJson(obj: Object) {
let result: Example = new Example();
for (let index in obj) {
if (Example.hasOwnProperty(index)) { // never runs because false
result[index] = obj[index];
}
/* allready tried this -> same result */
// if (result.hasOwnProperty(index)) {
// result[index] = obj[index];
//}
// let descriptor = Object.getOwnPropertyDescriptor(Example, index); // = undefined
// let descriptor = Object.getOwnPropertyDescriptor(result, index); // = undefined
}
return result;
}
public toJsonString() {
return JSON.stringify(this);
}
public toJsonObject() {
return JSON.parse(this.toJsonString());
}
}
let a = new Example('one');
let json = a.toJsonObject(); // this looks exactly like my api response (type json)
let obj = Example.fromJson(json);
console.log(json);
console.log(obj);
但console.log(obj)
必须<Example> {"Foo": "one", foo(...)}
编辑:生成的JavaScript:
var Example = (function () {
function Example(input) {
if (!!input) {
this.foo = input;
}
}
Object.defineProperty(Example.prototype, "foo", {
get: function () {
return this.Foo;
},
set: function (value) {
this.Foo = value;
},
enumerable: true,
configurable: true
});
Example.fromJson = function (obj) {
var result = new Example();
for (var index in obj) {
if (Example.hasOwnProperty(index)) {
result[index] = obj[index];
}
}
return result;
};
Example.prototype.toJsonString = function () {
return JSON.stringify(this);
};
Example.prototype.toJsonObject = function () {
return JSON.parse(this.toJsonString());
};
return Example;
}());
var a = new Example('one');
var json = a.toJsonObject(); // this looks exactly like my api response (type json)
var obj = Example.fromJson(json);
console.log(json);
console.log(obj);
class Example {
private Foo: string = undefined;
private Foo2: number = undefined;
constructor(input?: string) {
if (!!input) {
this.foo = input;
}
}
set foo(value: string) {
this.Foo = value;
}
get foo(): string {
return this.Foo;
}
set numeric(value: number) {
this.Foo2 = value;
}
get numeric(): number {
return this.Foo2;
}
public static fromJson(obj: Object) {
let result: Example = new Example();
for (let index in obj) {
if (result.hasOwnProperty(index)) {
result[index] = obj[index]; // care, has to be result
}
}
return result;
}
public toJsonString() {
return JSON.stringify(this);
}
public toJsonObject() {
return JSON.parse(this.toJsonString());
}
}
let a = new Example('one');
let json = a.toJsonObject();
let obj = Example.fromJson(json);
console.log(json);
console.log(obj);
我认为这就是您正在寻找的解决方案。 积极的影响,如果使用 undefined 初始化属性,则 toJson 方法不会列出参数。 因此,您的请求流量没有那么大。