我正在尝试在Bootstrap弹出窗口内使用表单。一些基本的HTML起作用(文本样式,按钮(,但表格不做。(也不要做onclick((javaScript操作(
我尝试了几个选项,但找不到任何解决方案。
<!doctype html>
<html lang="en">
<head>
<!-- Required meta tags -->
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1, shrink-to-fit=no">
<!-- Bootstrap CSS -->
<link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.3.1/css/bootstrap.min.css" integrity="sha384-ggOyR0iXCbMQv3Xipma34MD+dH/1fQ784/j6cY/iJTQUOhcWr7x9JvoRxT2MZw1T" crossorigin="anonymous">
<title>Hello, world!</title>
</head>
<body>
<button type="button" class="btn btn-lg btn-danger" data-toggle="popover" data-html='true' data-content="
<h3>This works</h3>
<form>
This does not:<br>
<input type='text' name='firstname'><br>
Last name:<br>
<input type='text' name='lastname'>
</form>
">popover with html form</button>
<!-- Optional JavaScript -->
<!-- jQuery first, then Popper.js, then Bootstrap JS -->
<script src="https://code.jquery.com/jquery-3.3.1.slim.min.js" integrity="sha384-q8i/X+965DzO0rT7abK41JStQIAqVgRVzpbzo5smXKp4YfRvH+8abtTE1Pi6jizo" crossorigin="anonymous"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/popper.js/1.14.7/umd/popper.min.js" integrity="sha384-UO2eT0CpHqdSJQ6hJty5KVphtPhzWj9WO1clHTMGa3JDZwrnQq4sF86dIHNDz0W1" crossorigin="anonymous"></script>
<script src="https://stackpath.bootstrapcdn.com/bootstrap/4.3.1/js/bootstrap.min.js" integrity="sha384-JjSmVgyd0p3pXB1rRibZUAYoIIy6OrQ6VrjIEaFf/nJGzIxFDsf4x0xIM+B07jRM" crossorigin="anonymous"></script>
<script>
$(function () {
$('[data-toggle="popover"]').popover({
html: true
})
})
</script>
</body>
</html>
您的html很好并且有效(请参见下面的示例。(问题是需要设置一个新标志以允许BS 4.3.1
在popover中允许HTML根据其该版本的发行说明是一个打破的变化:
"安全性:修复了我们的Tooltip和Popover插件中的XSS漏洞(CVE-2019-8331(,通过实现新的HTML消毒剂"
请参阅以下示例中的消毒实现:
$(function() {
$('[data-toggle="popover"]').popover({
html: true,
sanitize: false,
})
})
<link href="https://stackpath.bootstrapcdn.com/bootstrap/4.3.1/css/bootstrap.min.css" rel="stylesheet" />
<script src="https://code.jquery.com/jquery-3.3.1.slim.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/popper.js/1.14.7/umd/popper.min.js"></script>
<script src="https://stackpath.bootstrapcdn.com/bootstrap/4.3.1/js/bootstrap.min.js"></script>
<button style="margin: 20px;" type="button" class="btn btn-lg btn-danger" data-toggle="popover" data-html='true' data-content="
<h3>This works</h3>
<form>
This does too:<br>
<input type='text' name='firstname'><br>
Last name:<br>
<input type='text' name='lastname'>
</form>
">popover with html form</button>
<button style="margin: 20px;" type="button" class="btn btn-lg btn-info" data-toggle="popover" data-html='true' data-content="
<h3>This works</h3>
<form>
This does duece:<br>
<input type='text' name='firstname'><br>
Last name:<br>
<input type='text' name='lastname'>
</form>
">Duece</button>
您可以使用内容回调。无论如何,您需要将HTML插入隐藏的元素,而不是将其插入按钮:
$('[data-toggle="popover"]').popover({
html: true,
content: function () {
var content = $(this).attr("data-popover-content");
return $(content).find(".popover-body").clone();
}
})
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.3.1/css/bootstrap.min.css">
<script src="https://cdnjs.cloudflare.com/ajax/libs/popper.js/1.14.7/umd/popper.min.js"></script>
<script src="https://stackpath.bootstrapcdn.com/bootstrap/4.3.1/js/bootstrap.min.js"></script>
<button type="button" class="btn btn-lg btn-danger" data-toggle="popover" data-html='true'
data-popover-content="#yourContentHere">popover with html form
</button>
<div id="yourContentHere" style="display:none;">
<div class="popover-body">
<h3>This works</h3>
<form>
This does not:<br>
<input type='text' name='firstname'><br>
Last name:<br>
<input type='text' name='lastname'>
</form>
</div>
</div>
如果没有任何作用,请尝试此
$('#'+$(this).attr('aria-describedby')).find('.popover-body').html(myhtml);