需要关于根据日期和状态订购某些项目/事件的最有效方法的想法。
目前我有以下查询。
select tevent.ID, tevent.ename, e_dates.edate, tevent.status, tevent.eactive from tevent
LEFT JOIN e_dates on tevent.ID=e_dates.EID) Where tevent.status <> 'delete' and tevent.eactive ='Y' group by tevent.id order
by (case when tevent.status = 'closed' and e_dates.edate >= curdate() then 0
else 1 end), edates.edate desc
我使用了一个案例,但它对状态进行了排序,然后按日期排序,这让人们感到困惑。
下面是输出
+----+--------------+-----+-----------+
| ID |Edate | Ename | Status |
+----+--------------+-----+-----------+
| 2 | 2018-09-21 | Event2 | Closed |
| 5 | 2018-09-15 | Event5 | Closed |
| 3 | 2018-12-12 | Event3 | Open |
| 6 | 2018-10-25 | Event6 | Approved|
| 4 | 2018-10-25 | Event4 | Open |
| 7 | 2018-10-15 | Event7 | Pending |
| 10 | 2018-10-01 | Event10 | Open |
| 1 | 2018-09-30 | Event1 | Open |
| 4 | 2018-09-30 | Event4 | Open |
| 8 | 2018-09-01 | Event8 | Closed |
| 11 | 2018-08-25 | Event11 | Closed |
+----+--------------+-----+-----------+
编辑:我试图完成的是列出事件日期在事件日期之前保留在顶部的已关闭事件。 IE(ID 2 和 ID 5(
但希望 ASC 按时间顺序列出"打开"、"已批准"、"挂起"的事件状态。
和关闭事件,其中事件日期(edate(晚于底部列出的当前日期(now(((
例如:
+----+--------------+-----+-----------+
| ID |Edate | Ename | Status |
+----+--------------+-----+-----------+
| 2 | 2018-09-21 | Event2 | Closed |
| 5 | 2018-09-15 | Event5 | Closed |
| 1 | 2018-09-30 | Event1 | Open |*
| 4 | 2018-09-30 | Event4 | Open |*
| 10 | 2018-10-01 | Event10 | Open |*
| 7 | 2018-10-15 | Event7 | Pending |*
| 4 | 2018-10-25 | Event4 | Open |*
| 6 | 2018-10-25 | Event6 | Approved|*
| 3 | 2018-12-12 | Event3 | Open |*
| 11 | 2018-08-25 | Event11 | Closed |
| 8 | 2018-09-01 | Event8 | Closed |
+----+--------------+-----+-----------+
我认为你几乎是对的。您的案例陈述中需要三个选项 - 0 表示顶部的所有封闭选项,2 表示底部的所有封闭选项,1 表示中间的其他所有选项。 然后删除日期上的 desc,以使日期在每个部分中升序,因此您的 order by 子句应如下所示
order by (
case when tevent.status = 'closed' and e_dates.edate >= curdate() then 0
when tevent.status = 'closed' and e_dates.edate < curdate() then 2
else 1 end
), edates.edate
或者你可以写同样的东西
order by (
case when tevent.status = 'closed'
then case when e_dates.edate >= curdate() then 0 else 2 end
else 1 end
), edates.edate