如果有人有经验，这个问题与HECRAS有关，但总的来说，这只是一个关于将文本文件写入非常特定的格式以供HECRAS软件读取的问题。
基本上，我正在读取一些文件并更改一些数字，然后将其写回去，但我似乎无法完美匹配初始格式。
原始文件如下所示：
Type RM Length L Ch R = 1 ,229.41 ,21276,21276,21276
Node Last Edited Time=Oct-17-2019 15:52:28
#Sta/Elev= 452
0 20.097 67.042 9.137 67.43 9.139 68.208 9.073 68.598 9.129
68.986 9.086 70.538 9.071 70.926 9.042 71.984 9.046 72.48 9.025
73.646 9.056 74.368 9.034 75.586 9.042 76.55 9.017 77.138 9.047
78.304 8.989 79.47 9.025 80.19 9.001 81.41 9.003 81.974 8.978
83.83 9.005 85.284 9.079 85.682 9.068 86.97 9.118 88.012 9.223
88.79 9.239 89.65 9.316 90.342 9.324 91.134 9.475 91.966 9.525
92.282 9.589 93.346 9.546 94.222 9.557 94.922 9.594 95.71 9.591
96.546 9.64 97.286 9.574 98.87 9.688 99.258 9.673 99.642 9.712
#Mann= 3 , 0 , 0
0 .09 0 246.4 .028 0 286.4 .09 0
Bank Sta=246.4,286.4
XS Rating Curve= 0 ,0
XS HTab Starting El and Incr=1.708,0.1, 500
XS HTab Horizontal Distribution= 5 , 5 , 5
Exp/Cntr=0.3,0.1
我对 Sta/Elev 数据感兴趣...它看起来像一些正确的对齐制表符/空格？在车站/高程对中分隔格式，每行 5 个。.也许每对 16 个字符？？
我尝试了很多不同的东西，我当前的代码是：
with open('C:/Users/deden/Desktop/t/test.g01','w') as out:
out.write(txt[:idx[0][0]])
out.write(txt[idx[0][0]:idx[0][0]+bounds[0]])
out.write('#'+raw_SE.split('n')[0]+'n')
i = 0
while i <= len(new_SE):
out.write('t'.join(new_SE[i:i+10])+'n')
i+=10
out.write(txt[idx[0][0]+bounds[1]:idx[1][0]])
这是一个有点笨拙的ATM，仍在努力解决，重要的部分只是：
while i <= len(new_SE):
out.write('t'.join(new_SE[i:i+10])+'n')
i+=10
new_SE只是一个车站/海拔列表：
['0', '30.097', '67.042', '19.137', '67.43', '19.139', '68.208', '19.073', '68.598', '19.128999999999998' ...]
我还尝试用这样的东西来玩弄合理的一面：
'%8s %8s' % (tmp[0], tmp[1])
文本之间基本上有 8 个空格，但正确对齐它们
老实说挣扎...如果有人可以在 #Sta/Elev= 452 和 #Mann 之间重新创建原始文本，我将永远感激不尽，如果有人想试一试，这里是完整列表：
new_SE = ['0', '30.097', '67.042', '19.137', '67.43', '19.139', '68.208', '19.073', '68.598', '19.128999999999998', '68.986', '19.086', '70.538', '19.070999999999998', '70.926', '19.042', '71.984', '19.046', '72.48', '19.025', '73.646', '19.055999999999997', '74.368', '19.034', '75.586', '19.042', '76.55', '19.017', '77.138', '19.047', '78.304', '18.989', '79.47', '19.025', '80.19', '19.000999999999998', '81.41', '19.003', '81.974', '18.978', '83.83', '19.005000000000003', '85.284', '19.079', '85.682', '19.067999999999998', '86.97', '19.118000000000002', '88.012', '19.223', '88.79', '19.239', '89.65', '19.316000000000003', '90.342', '19.323999999999998', '91.134', '19.475', '91.966', '19.525', '92.282', '19.589', '93.346', '19.546', '94.222', '19.557000000000002', '94.922', '19.594', '95.71', '19.591', '96.546', '19.64', '97.286', '19.573999999999998', '98.87', '19.688000000000002', '99.258', '19.673000000000002', '99.642', '19.712']
不确定我是否正确理解 - 请考虑看看
# with open('C:/Users/deden/Desktop/t/test.g01','w') as out:
for i in range(0, len(new_SE), 10):
row = [f'{float(v):8.3f}' for v in new_SE[i:i+10]]
out.write(''.join(r) + 'n')
# 0.000 30.097 67.042 19.137 67.430 19.139 68.208 19.073 68.598 19.129
# 68.986 19.086 70.538 19.071 70.926 19.042 71.984 19.046 72.480 19.025
# 73.646 19.056 74.368 19.034 75.586 19.042 76.550 19.017 77.138 19.047
# 78.304 18.989 79.470 19.025 80.190 19.001 81.410 19.003 81.974 18.978
# 83.830 19.005 85.284 19.079 85.682 19.068 86.970 19.118 88.012 19.223
# 88.790 19.239 89.650 19.316 90.342 19.324 91.134 19.475 91.966 19.525
# 92.282 19.589 93.346 19.546 94.222 19.557 94.922 19.594 95.710 19.591
# 96.546 19.640 97.286 19.574 98.870 19.688 99.258 19.673 99.642 19.712