属性错误："str"对象没有属性"公司"

Question

我想不通。我想我对如何调用一个对象是错的。对象显然不被称为公司名称。

注册客户后，选择2进入子菜单显示客户列表，然后写下客户名称以显示有关特定客户的更多信息

# APP REVOLUTIO SOLUTIONS - OverView ARS v1.0

class OVARS:
def __init__(self, company, kNr, adr, tlf, sp, app, appV, date, afd, ini):
self.company = company
self.kNr = kNr
self.adr = adr
self.tlf = tlf
self.sp = sp
self.app = app
self.appV = appV
self.date = date
self.afd = afd
self.ini = ini

class udskriv(OVARS):
def __init__(self):
super(OVARS, self).__init__()

def udskriv_kunde(self, cuna):
print(cuna.company)
print(cuna.kNr)
print(cuna.adr)
print(cuna.tlf)
print(cuna.sp)
print(cuna.app)
print(cuna.appV)
print(cuna.date)
print(cuna.afd)
print(cuna.ini)

######################## PROGRAM START ########################
udskrivKALD = udskriv()
print('OverView ARS v1.0')

customerList = []
i = 0
while True:
try:
menuChoice = int(input('''
1. apply new customer
2. show existing customers
3. exit
n'''))
except ValueError:
print('choice not accepted.n')
continue
print()
if menuChoice == 1:
addCompanyName = input('enter company name: ')
addKundeNr = input('enter customer ID.: ')
addAdresse = input('enter address: ')
addTelefon = input('enter telephone nr.: ')
addSP = input('enter Servicepackage: ')
addApp = input('enter app: ')
addAppV = input('enter App version: ')
addDate = input('enter Date: ')
addAfd = input('enter department: ')
addIni = input('enter Inititials: ')
customerList.append(addCompanyName)
print('ncustomer registered: ' + str(addCompanyName) + 'n')
newCustomer = addCompanyName
newCustomer = OVARS(addCompanyName, addKundeNr, addAdresse, addTelefon, addSP, addApp, addAppV, addDate, addAfd, addIni)
continue

elif menuChoice == 2:
i = 0
j = 0
k = 1
for i in customerList:
print(str(k) + ': ' + customerList[j])
j += 1
k += 1

subMenu2Choice = input('''
choose customer to show customer information,
or choose 0 to go back to first menu
n''')

if subMenu2Choice == 0:
continue
elif subMenu2Choice in customerList:
udskrivKALD.udskriv_kunde(subMenu2Choice)
else:
print('wrong choice')
continue

elif menuChoice == 3: # Exiting Program
break

else:
print('choice not accepted.n')
continue
#udskrivKALD.udskriv_kunde(newCustomer)

print()
# END OF PROGRAM

请帮助D:

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Answer 1

这里有一个快速解决方案：

正如有人在评论中提到的那样，您正试图将字符串传递给期望特定对象的函数。您可以使用customerList来存储所有创建的对象，而不仅仅是company属性：

customerList.append(newCustomer)

对于显示现有客户修复，请使用以下片段：

elif any(i.company==subMenu2Choice for i in customerList):
for i in customerList:
if i.company==subMenu2Choice:udskrivKALD.udskriv_kunde(i) 

代码：

# APP REVOLUTIO SOLUTIONS - OverView ARS v1.0
class OVARS:
def __init__(self, company, kNr, adr, tlf, sp, app, appV, date, afd, ini):
self.company = company
self.kNr = kNr
self.adr = adr
self.tlf = tlf
self.sp = sp
self.app = app
self.appV = appV
self.date = date
self.afd = afd
self.ini = ini
class udskriv(OVARS):
def __init__(self):
super(OVARS, self).__init__()
def udskriv_kunde(self, cuna):
print(cuna.company)
print(cuna.kNr)
print(cuna.adr)
print(cuna.tlf)
print(cuna.sp)
print(cuna.app)
print(cuna.appV)
print(cuna.date)
print(cuna.afd)
print(cuna.ini)
######################## PROGRAM START ########################
udskrivKALD = udskriv()
print('OverView ARS v1.0')
customerList = []
i = 0
while True:
try:
menuChoice = int(input('''
1. apply new customer
2. show existing customers
3. exit
n'''))
except ValueError:
print('choice not accepted.n')
continue
print()
if menuChoice == 1:
addCompanyName = input('enter company name: ')
addKundeNr = input('enter customer ID.: ')
addAdresse = input('enter address: ')
addTelefon = input('enter telephone nr.: ')
addSP = input('enter Servicepackage: ')
addApp = input('enter app: ')
addAppV = input('enter App version: ')
addDate = input('enter Date: ')
addAfd = input('enter department: ')
addIni = input('enter Inititials: ')

print('ncustomer registered: ' + str(addCompanyName) + 'n')
newCustomer = addCompanyName
newCustomer = OVARS(addCompanyName, addKundeNr, addAdresse, addTelefon, addSP, addApp, addAppV, addDate, addAfd, addIni)
customerList.append(newCustomer)
continue

elif menuChoice == 2:
i = 0
j = 0
k = 1
for i in customerList:
print(str(k) + ': ' + customerList[j].company)
j += 1
k += 1

subMenu2Choice = input('''
choose customer to show customer information,
or choose 0 to go back to first menu
n''')

if subMenu2Choice == 0:
continue
elif any(i.company==subMenu2Choice for i in customerList):
for i in customerList:
if i.company==subMenu2Choice:udskrivKALD.udskriv_kunde(i)
else:
print('wrong choice')
continue

elif menuChoice == 3: # Exiting Program
break

else:
print('choice not accepted.n')
continue
#udskrivKALD.udskriv_kunde(newCustomer)

print()
# END OF PROGRAM