我所拥有的是一个连接到web服务的Java代码,我试图将一些数据添加到页面。当我进行调试时,代码工作得很好,但当我试图实时运行它时,我遇到了一些问题。下面是我的Java代码:
public class PersonalInfo extends Activity{
private GoogleMap googleMap;
LocationManager mLocationManager;
Geocoder geocoder;
EditText addressnew;
GPSTracker gps;
boolean loginStatus;
String Item_Name;
String Item_Price;
String Item_Quantity;
String Total_Price;
String Customer_Name;
String Customer_Number;
String Customer_Address;
ArrayList<String> mixlist=new ArrayList<String>();
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
this.requestWindowFeature(Window.FEATURE_NO_TITLE);
setContentView(R.layout.personal_info);
final EditText name=(EditText)findViewById(R.id.edittext1);
final EditText mobile=(EditText)findViewById(R.id.edittext2);
addressnew=(EditText)findViewById(R.id.editText3);
final Button locationnew=(Button)findViewById(R.id.button1);
Button send=(Button)findViewById(R.id.button2);
send.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
// TODO Auto-generated method stub
try{
Intent newintent = getIntent();
mixlist=newintent.getStringArrayListExtra("listmix");
Log.e("listmix",mixlist+"");
for(int i=0;i<=mixlist.size();i++){
if(i==mixlist.size()){
Item_Name="0";
Item_Price="0";
Item_Quantity="0";
Total_Price="0";
Customer_Name=name.getText().toString();
Log.e("customer_name",Customer_Name);
Customer_Number=mobile.getText().toString();
Customer_Address=addressnew.getText().toString();
//Call execute
AsyncCallWS task = new AsyncCallWS();
task.execute();
}
else{
Item_Name=mixlist.get(i);
i++;
Item_Price=mixlist.get(i);
i++;
Item_Quantity=mixlist.get(i);
i++;
Total_Price=mixlist.get(i);
Customer_Name="0";
Customer_Number="0";
Customer_Address="0";
// AsyncCallWSnew tasknew = new AsyncCallWSnew();
//Call execute
AsyncCallWS task = new AsyncCallWS();
task.execute();
}
}
}
catch(Exception e){
e.printStackTrace();
}
}
});
// mLocationManager = (LocationManager) getSystemService(LOCATION_SERVICE);
// locationnew.setOnClickListener(new OnClickListener() {
//
// @Override
// public void onClick(View v) {
// }
// });
//
//
}
@Override
public void onBackPressed() {
Log.d("CDA", "onBackPressed Called");
Intent setIntent = new Intent(PersonalInfo.this,MainActivity.class);
setIntent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
startActivity(setIntent);
}
private class AsyncCallWS extends AsyncTask<Void, Void, Void> {
protected void onPostExecute(Void result) {
//Make Progress Bar invisible
Toast.makeText(getApplicationContext(), "order has been sent", Toast.LENGTH_LONG).show();
Intent intObj = new Intent(PersonalInfo.this,MainActivity.class);
startActivity(intObj);
//Error status is false
}
//Make Progress Bar visible
protected void onPreExecute() {
}
@Override
protected Void doInBackground(Void... params) {
// TODO Auto-generated method stub
loginStatus = WebService.invokeLoginWS(Item_Name,Item_Price,Item_Quantity, Total_Price, Customer_Name,
Customer_Number, Customer_Address,"InsertData");
return null;
}
}
}
现在,例如,mix列表是:
[orange, 2, 3, 6.0, Tomato, 0.3, 6, 1.7999999999999998]
它将添加第一个索引为项目名称,项目价格,item_quantity, total_price,然后其他值(customer-name=0, customer_number=0, customer_address=0)和执行asynctask,数组完成后,它将做相反的,我将填充(项目名称,项目价格,item_quantity, total_price) =0和其他值将从编辑文本中获取。并执行asynctask ..在调试模式下,它工作得很好。在实时中,它会像在这个数组中一样反转值,它只会添加橙色,2,3,6.0,其他三个值将重复两次!!
为什么会这样?
在for循环中创建异步任务的多个对象,其中每个对象在单独的线程上运行这是并行运行的,它可能会发生,你的第二个线程完成第一个和第一个线程完成在最后或任何顺序,这就是为什么他们不插入数据在正确的顺序,但在随机顺序。