没有参数的构造函数

Question

我有这个类，但我需要以一种构造函数(public StemmingAndLemmatization(TurkishMorphParser parser))没有参数(public StemmingAndLemmatization())的方式来编写它!我怎么转换它??任何想法?

    public class StemmingAndLemmatization {
        TurkishMorphParser parser;
        public StemmingAndLemmatization(TurkishMorphParser parser) {
            this.parser = parser;
        }
        public void parse(String word) {
            System.out.println("Word = " + word);
            System.out.println("Parses: ");
            List<MorphParse> parses = parser.parse(word);
            for (MorphParse parse : parses) {
                System.out.println(parse.formatLong());
                System.out.println("tStems = " + parse.getStems());
                System.out.println("tLemmas = " + parse.getLemmas());
            }
        }
        public static void main(String[] args) throws IOException {
            TurkishMorphParser parser = TurkishMorphParser.createWithDefaults();
            new StemmingAndLemmatization(parser).parse("kitabımızsa");
        }
    }

Answer 1

您需要将构造函数的功能替换为将接受解析器的方法，或者您可以让构造函数创建自己的解析器。

public class StemmingAndLemmatization {
    TurkishMorphParser parser;
    public void setParser(TurkishMorphParser parser) {
       this.parser = parser;
    }

或

public StemmingAndLemmatization(TurkishMorphParser) {
     this.parser = TurkishMorphParser.createWithDefaults();
 }