将字符串转换为日期(复杂时区)

Question

我有非常不规则的日期，比如：

2012年1月9日星期一14:18:32-0800（GMT）

2006年10月18日00:32:03-0000

2006年11月18日星期六19:52:23 UT

我做了一个非常复杂的函数来完成这一切，它很有效，但为了学习，我想用try-and-catch再做一次。我的问题是，我该如何处理时区？你可以在我的函数中看到所有的时区，但我也有一些时间（…例如，作为时区，我不想将所有情况存储在字符串数组中。

我还想使用Joda Time（它可以是localDate或dateTime，对我来说没那么重要）。

public LocalDate handleDate(String date) {
        String[] days = { "Mon", "Tue", "Wed", "Thu", "Fri", "Sat", "Sun" };
        String[] months = { "Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul",
                "Aug", "Sep", "Oct", "Nov", "Dec" };
        String[] years = { "2004", "2005", "2006", "2007", "2008", "2009",
                "2010", "2011", "2012" };
        // ORDER IS VERRY IMPORTANT!! ( MEST must be before EST for example)
        String[] timesZones = { "BST", "CET", "CEST", "CST", "CDT", "EDT",
                "GMT+00:00", "GMT", "IST", "MEST", "EST", "MET", "MDT", "PST",
                "PDT", "SAST", "UTC", "UT", "W. Europe Standard Time",
                "West-Europa (zomertijd)" };
        String origDate = date;
        String timeZone = "";
        String year = "";
        String month = "";
        String day = "";
        int hours = 0;
        int minutes = 0;
        int seconds = 0;
        // is it valid?
        date = trim(date);
        if (date.equals("")) {
            return null;
        }
        // first delete the comma that comes mostly after the day
        date = date.replaceAll(",", "");
        // remove the day
        for (int i = 0; i < days.length; i++) {
            if (date.contains(days[i])) {
                date = date.replace(days[i], "");
                break;
            }
        }
        // if(date.contains("23:27:17")) println(date);
        for (int i = 0; i < timesZones.length; i++) {
            // first check with '(' and ')'
            String target = "(" + timesZones[i] + ")";
            if (date.contains(target)) {
                timeZone = timesZones[i];
                date = date.replace(target, "");
                break;
            }
            // if not found check without '(' and ')'
            if (date.contains(timesZones[i])) {
                timeZone = timesZones[i];
                date = date.replace(timesZones[i], "");
                break;
            }
        }
        // get the month
        for (int i = 0; i < months.length; i++) {
            if (date.contains(months[i])) {
                month = months[i].toLowerCase(); // !must be lowercase
                // must be dutch on my pc
                if (month.equals("oct"))
                    month = "okt";
                if (month.equals("may"))
                    month = "mei";
                if (month.equals("mar"))
                    month = "mrt";
                date = date.replace(months[i], "");
                break;
            }
        }
        // get the year
        for (int i = 0; i < years.length; i++) {
            if (date.contains(years[i])) {
                year = years[i];
                date = date.replace(years[i], "");
                break;
            }
        }
        // get the time
        Pattern p = Pattern.compile("(\d\d):(\d\d):(\d\d)");
        Matcher m = p.matcher(date);
        if (m.find()) {
            // also fix the time, 00 is not allowed
            hours = Integer.parseInt(m.group(1));
            minutes = Integer.parseInt(m.group(2));
            seconds = Integer.parseInt(m.group(3));
            date = date.replaceAll("(\d\d:\d\d:\d\d)", "");
        }
        // get the time difference
        date = date.replace("+-", "+0"); // bug fix where data is incorrect ( 16
                                            // Sep 2007 23:27:17 +-200)
        p = Pattern.compile("[+|-]*(\d\d)\d\d");
        m = p.matcher(date);
        if (m.find()) {
            int timeDifferenceH = Integer.parseInt(m.group(1));
            date = date.replaceAll("([+|-]*\d\d\d\d)", "");
        }
        date = " " + date; // bug fix
        // get the day
        for (int i = 31; i >= 1; i--) {
            // first check for the ones that contains 2 digits (like 07)
            String d = nf(i, 2);
            if (date.contains(d)) {
                day = nf(i, 2);
                date = date.replace(d, "");
                break;
            }
            // check for 1 digit
            d = "" + i;
            if (date.contains(d)) {
                day = nf(i, 2);
                date = date.replace(d, "");
                break;
            }
        }
        // there should be nothing left except white space
        date = date.replace(" ", "");
        if (date.equals("") == false) {
            println("handleDate: problem with inputn" + date);
            println(origDate + "n");
            println(year);
            println(month);
            println(day);
        }
        // String cleanDate = day + "/" + month + "/" + year + " " + nf(hours,
        // 2) + ":" + nf(minutes, 2) + ":" + nf(seconds, 2);
        // DateTimeFormatter formatter =
        // DateTimeFormat.forPattern("dd/MMM/yyyy HH:mm:ss");
        String cleanDate = year + "-" + month + "-" + day;
        DateTimeFormatter formatter = DateTimeFormat.forPattern("yyyy-MMM-dd");
        try {
            // DateTime dt = formatter.parseDateTime(cleanDate);
            // LocalDate dt = new LocalDate(cleanDate);
            // return dt.toLocalDate();
            // return dt;
            // return new LocalDate().parse(cleanDate, formatter);
            return formatter.parseLocalDate(cleanDate);
        } catch (IllegalArgumentException iae) {
            println("handleDate: Problem with formatting: " + cleanDate);
        }
        return null;
    }

Answer 1

JodaTime中的DateTimeFormatter类在这方面非常强大和灵活，您应该尝试Custom Formatters或Freaky Formatters