为什么我的代码使用提供的集合输出荒谬的数字？我正在尝试字符串格式

Question

我使用的是这些数字：5,4,3.5,10,20,40,80,93.33，-1。它将适用于只有5个数字的简单事物，如：5,4,3,2,1。发生了什么事？如果有问题的话，我会尝试使用String.format来缩短数字。你们注意到我的代码中有什么我可以做的不同的事情吗。这是所提供集合的输出：

The minimum is -1.0, the maximum is 2.147483647E9, and the average is 2.38609322E8
-238609317.00
-238609318.00
1908874325.00
-238609312.00
-238609302.00
-238609282.00
-238609242.00
-238609229.00
-238609323.00    

期望输出

最小值为3.5，最大值为93.33，平均值为31.978749999999998

平均得分5.0为-26.978749999999998

平均得分4.0为-27.978749999999998

平均得分3.5为-28.478749999999998

得分10.0为平均的-21.978749999999998

平均得分20.0为-11.978749999999998

平均得分40.0为8.021250000000002

得分80.0是平均的48.02125

平均得分93.33为61.35125

public static void main(String[] args)
{
  int count = 0;
  int arrayLength;
  double min = 99999;
  double max = 0;
  double average;
  double sum = 0;
  JOptionPane.showMessageDialog(null, "This program will display the average as well as each numbers distance from the average");
  // need to put loop here.
  arrayLength = IO.readInt("How many numbers will you be entering?");
  if (arrayLength <= 0 || arrayLength > 100)
  {
     JOptionPane.showMessageDialog(null, "Nothing entered, program will close.");
     System.exit(0);
  }
  double[] array = new double[arrayLength];
  for (int i = 0; i <arrayLength; i++)
  {
     array[i] = IO.readInt("Enter number: " + (i+1));
     count++;  
  } 
  for (int i = 0; i <arrayLength; i++)
  {
     sum = (array[i] + sum);
     if (array[i] <= min)
     {
        min = array[i];
     }
     if (array[i] > max)
     {
        max = array[i];
     }
  }
  average = (sum / arrayLength);
  System.out.println("The minimum is " + min + ", the maximum is " + max + ", and the average is " + average);
  double[] array2 = new double[arrayLength];
  for (int i = 0; i <arrayLength; i++)
  {
     array2[i] = (array[i] - average);
  }
  for (int i = 0; i <arrayLength; i++)
  {
     System.out.println(String.format("%.2f", array2[i]));
  }

}

Answer 1

我不知道当你做IO.readInt并将其放入double时会发生什么，但它不可能是你想要的。。。