如何使用 JObject 解析此 Json 字符串

Question

[
  ["Sender", "[e-mail]"], 
  ["Date", "Sat, 19 Dec 201520:41:31 +0000"], 
  ["X-Mailgun-Sid", "WyI0ZjRjNyIsICJyYWplZXZrbXh4eddHh4eDMzMzMzQHlhaG9vLmNvbSIsICJjNGExZiJd"],
  ["Received", "by luna.mailgun.net with HTTP; Sat, 19 Dec 2015 20:41:31+0000"], 
  ["Message-Id", "<[e-mail]>"], 
  ["Reply-To", "[e-mail]"], 
  ["X-Mailgun-Skip-Verification", "false"], 
  ["To", "John Myers <[e-mail]>"], ["From", ""Inc." <[e-mail]>"], 
  ["Subject", "Test subject"],
  ["Mime-Version", "1.0"], 
  ["Content-Type", 
      ["multipart/mixed", { "boundary": "e43d638b70f04a40889d14f4c8422953" } ]
  ]
]

使用 JObject

(VB.net( 时，JObject.parse 会抛出此错误：

Error reading JObject from JsonReader. Current JsonReader item is not an object: StartArray. Path '', line 2, position 2.---- at Newtonsoft.Json.Linq.JObject.Load(JsonReader reader) at Newtonsoft.Json.Linq.JObject.Parse(String json)

但是当我将上述字符串复制到在线 Json 查看器中时，他们似乎都解析得很好。

Answer 1

您的 JSON 不代表一个对象;它是一个数组(数组(。 因此，您不能使用 JObject.Parse() 。 相反，请使用可以处理数组的 JArray.Parse()，或者使用 JToken.Parse() ，它可以处理数组或对象。

string json = @"
[
  [""Sender"", ""[e-mail]""], 
  [""Date"", ""Sat, 19 Dec 201520:41:31 +0000""], 
  [""X-Mailgun-Sid"", ""WyI0ZjRjNyIsICJyYWplZXZrbXh4eddHh4eDMzMzMzQHlhaG9vLmNvbSIsICJjNGExZiJd""],
  [""Received"", ""by luna.mailgun.net with HTTP; Sat, 19 Dec 2015 20:41:31+0000""], 
  [""Message-Id"", ""<[e-mail]>""], 
  [""Reply-To"", ""[e-mail]""], 
  [""X-Mailgun-Skip-Verification"", ""false""], 
  [""To"", ""John Myers <[e-mail]>""], 
  [""From"", """"Inc."" <[e-mail]>""], 
  [""Subject"", ""Test subject""],
  [""Mime-Version"", ""1.0""], 
  [""Content-Type"", 
      [""multipart/mixed"", { ""boundary"": ""e43d638b70f04a40889d14f4c8422953"" } ]
  ]
]";
JArray rows = JArray.Parse(json);
foreach (JArray row in rows)
{
    Console.WriteLine(string.Join(": ", row.Select(r => r.ToString())));
}

小提琴：https://dotnetfiddle.net/VRs47S