解析没有任何子节点的 Xml 文件

Question

我是安卓开发的新手，我想使用 Dom Parser解析一个特定的 xml 文件。xml结构是这样的。

<Images>
   <image link="a.tgcdn.net/images/products/zoom/e554_android_plush_robot.jpg"/>
   <image link="a.tgcdn.net/images/products/zoom/e554_android_plush_robot.jpg"/>
   <image link="http://cdn.androidpolice.com/wp-content/themes/ap1/images/android1.png"/>
   <image link="http://cdn.androidpolice.com/wp-content/themes/ap1/images/android1.png"/>
   <image link="http://cdn.androidpolice.com/wp-content/themes/ap1/images/android1.png"/>
</Images>

我想在数组列表中添加这些网络链接。建议我一些出路。.甚至与此相关的任何链接或教程也会有所帮助。谢谢。

这是完整的代码..

public class MainActivity extends Activity {

    String xmlurl       = "--url of xml---";

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        ArrayList<String> mImageLink = new ArrayList<String>();
        try {
            URL url = new URL(xmlurl);
            XMLParser   parser  =   new XMLParser();
            String      xml     = parser.getXMLfromUrl(url);
            Document    doc     = parser.getDomElement(xml);
            DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
            DocumentBuilder db = dbf.newDocumentBuilder();
            Document doc1 = db.parse(new InputSource(url.openStream()));
            doc1.getDocumentElement().normalize();
            NodeList nodeList = doc1.getElementsByTagName("photo");
            for (int i = 0; i < nodeList.getLength(); i++) {
                Element websiteElement = (Element) nodeList.item(i);
                nodeList = websiteElement.getChildNodes();              
                mImageLink.add(websiteElement.getAttribute("link"));
            }
        } catch (Exception e) {
            System.out.println("XML Pasing Excpetion = " + e);
        }
        for(int i=0;i<mImageLink.size();i++){
            Log.d("Photo link --- " + i,mImageLink.get(i));
        }
    }
    @Override
    public boolean onCreateOptionsMenu(Menu menu) {
        getMenuInflater().inflate(R.menu.activity_main, menu);
        return true;
    }
}

Answer 1

请使用以下代码使用 DOM 解析器解析上面的 XML 文件。

public class MainActivity extends Activity {
    ArrayList<String> mImageLink;
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        try {
            mImageLink = new ArrayList<String>();
            InputStream is = getResources().openRawResource(R.raw.temp);
            DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
            DocumentBuilder db = dbf.newDocumentBuilder();
            Document doc = db.parse(new InputSource(is));
            doc.getDocumentElement().normalize();
            NodeList nodeList = doc.getElementsByTagName("image");
            for (int i = 0; i < nodeList.getLength(); i++) {
                Node node = nodeList.item(i);
                Element fstElmnt = (Element) node;
                mImageLink.add(fstElmnt.getAttribute("link"));
            }
        } catch (Exception e) {
            System.out.println("XML Pasing Excpetion = " + e);
        }
    }
}

有关更多信息，请参见下面的链接。

使用 DOM 解析器的 XML 解析

Answer 2

使用 dom4j 库，它是 SAXReader。

    InputStream is = FileUtils.class.getResourceAsStream("file.xml");
    SAXReader reader = new SAXReader();
    org.dom4j.Document doc = reader.read(is);
    is.close();
    Element content = doc.getRootElement();  //this will return the root element in your xml file
    List<Element> methodEls = content.elements("element"); // this will retun List of all Elements with name "element" 

对于 DOM 解析，您可以使用同一个库的 DOMReader