我进入某种情况,即读取属性文件,并基于属性文件的值创建文件夹,并将资源从某些目录复制到它。
properties-file: xyz.properties
CLIENTLIST=A,B
我想在Maven中执行以下步骤。
1. From above properties file pom should read the property.
2. In loop I want to create folders by name A and B.
3. After creating folder i want to copy some resources into it.
ex: after creating folder A , want to copy some resource files from x/y/z directory.
在Maven中可以吗?
我使用几个插件做到了这一点,
<plugins>
<plugin>
<groupId>org.codehaus.mojo</groupId>
<artifactId>properties-maven-plugin</artifactId>
<version>1.0.0</version>
<executions>
<execution>
<id>read property file</id>
<phase>install</phase>
<goals>
<goal>read-project-properties</goal>
</goals>
<configuration>
<files>
<file>${basedir}/dirOne/xyz.properties</file>
</files>
</configuration>
</execution>
</executions>
</plugin>
<plugin>
<groupId>com.soebes.maven.plugins</groupId>
<artifactId>iterator-maven-plugin</artifactId>
<version>0.3</version>
<executions>
<execution>
<phase>install</phase>
<goals>
<goal>iterator</goal>
</goals>
<configuration>
<content>${CLIENTLIST}</content>
<pluginExecutors>
<pluginExecutor>
<plugin>
<artifactId>maven-resources-plugin</artifactId>
<version>2.6</version>
</plugin>
<goal>copy-resources</goal>
<configuration>
<outputDirectory>${basedir}/dirTwo/@item@/</outputDirectory>
<resources>
<resource>
<directory>${basedir}/src/main/resources/</directory>
<includes>
<include>**/*.xml</include>
<include>**/*.properties</include>
</includes>
<excludes><exclude>**/*.cmd</exclude></excludes>
</resource>
</resources>
</configuration>
</pluginExecutor>
</pluginExecutors>
</configuration>
</execution>
</executions>
</plugin>
</plugins>
</build>
我已经使用了读取属性,迭代器和复制资源插件来获取我需要的东西。
- 首先我读取属性文件。
- 在循环中迭代值,这些值从属性文件中读取。
- 并在循环中创建每个文件夹,并复制资源以创建文件夹。