是否可以计算NSString中两个单词之间的字符数？这是字符串
NSString *myString = [NSString stringWithFormat:@"This is a test string."];
我想计算单词"This"和单词"string"之间的字符数。
这可能是吗
您可以这样做：
NSString *myString = [NSString stringWithFormat:@"This is a test string."];
NSInteger charCountBetween = -1;
NSRange thisRange = [myString rangeOfString:@"This"];
NSRange stringRange = [myString rangeOfString:@"string"];
if( thisRange.location != NSNotFound && stringRange.location != NSNotFound )
{
charCountBetween = fabs(thisRange.location - stringRange.location);
if( thisRange.location > stringRange.location )
{
charCountBetween -= stringRange.length;
}
else
{
charCountBetween -= thisRange.length;
}
}
您必须首先找到范围并从中获取子字符串
NSString *myString = [NSString stringWithFormat:@"This is a test string."];
NSRange range1 = [myString rangeOfString:@"This"];
NSRange range2 = [myString rangeOfString:@"string"];
NSRange rangeSubString = NSMakeRange(range1.location + range1.length, range2.location - range1.location - range1.length);
NSString *subString = [myString substringWithRange:rangeSubString];
然后你可以计算这个字符串的字符
NSUInteger characterCount = [subString length];
NSString *myString = @"This is a test !";
NSRange match = [myString rangeOfString: @"This"];
NSRange match1 = [myString rangeOfString: @"test"];
int nbChar = match1.location - match.location;
这就是你要找的吗？
试试这个：
NSString *string = @"This is a test string";
NSRange firstRange = [string rangeOfString:@"This"];
NSRange secondRange = [string rangeOfString:@"string"];
if (firstRange.location != NSNotFound &&
secondRange.location != NSNotFound &&
secondRange.location > firstRange.location) {
NSLog(@"Characters between: %d", secondRange.location - (firstRange.location + firstRange.length));
}
您需要使用NSRange:
NSRange range1 = [myString rangeOfString:@"This"];
NSRange range2 = [myString rangeOfString:@"string"];
NSUInteger numberOfChars = range2.location - range1.location;