删除二维数组中的重复项，同时保持顺序

Question

我发现很多关于删除数组中重复项的线程，但没有一个线程用于我的特定用例。我有一个二维列表，我需要从中删除重复项，但我必须保持原始序列

mylist = [['Installation', '64%'], ['C2', '14%'], ['NA', '14%'], ['C2', '14%'], ['NA', '14%'], ['na', '7%']]

我需要简单地删除重复项而不重新排列，所以..

newlist = [['Installation', '64%'], ['C2', '14%'], ['NA', '14%'], ['na', '7%']]

感谢任何帮助

Answer 1

使用 set 跟踪看到的项目：

>>> mylist = [['Installation', '64%'], ['C2', '14%'], ['NA', '14%'], ['C2', '14%'], ['NA', '14%'], ['na', '7%']]
>>> seen = set()
>>> newlist = []
>>> for item in mylist:
...     t = tuple(item)
...     if t not in seen:
...         newlist.append(item)
...         seen.add(t)
...
>>> newlist
[['Installation', '64%'], ['C2', '14%'], ['NA', '14%'], ['na', '7%']]

注意

您需要将列表转换为元组（列表不可哈希）;无法添加要设置的列表。

>>> seen = set()
>>> seen.add([1,2])
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: unhashable type: 'list'
>>> seen.add(tuple([1,2]))
>>>

Answer 2

mylist = [['Installation', '64%'], ['C2', '14%'], ['NA', '14%'], ['C2', '14%'], ['NA', '14%'], ['na', '7%']]
result = []
for x in mylist:
    if x not in result:
        result.append(x)
print result

[['Installation', '64%'], ['C2', '14%'], ['NA', '14%'], ['na', '7%']]

Answer 3

np导入numpy：

myList = [['Installation', '64%'], ['C2', '14%'], ['NA', '14%'], ['C2', '14%'], ['NA', '14%'], ['na', '7%']]
mylist=np.unique(myList,axis=0)
print (mylist)