为什么教义要制造一次大迁徙

Question

>我创建了几个实体：

用户

namespace AppModels;
use DoctrineORMMapping as ORM;
use SymfonyComponentValidatorConstraints as Assert;
/**
 * @ORMEntity
 * @ORMTable(name="users")
 */
class User {
    /**
     * @ORMId
     * @ORMColumn(type="integer")
     * @ORMGeneratedValue
     */
    protected $id;
    /**
     * @ORMColumn(type="string", length=32, nullable=false)
     */
    protected $firstName;
    /**
     * @ORMColumn(type="string", length=32, nullable=false)
     */
    protected $lastName;
    /**
     * @ORMColumn(type="string", length=100, unique=true, nullable=false)
     */
    protected $userName;
    /**
     * @ORMColumn(type="string", length=100, unique=true, nullable=false)
     * @AssertEmail
     */
    protected $email;
    /**
     * @ORMColumn(type="string", length=500, nullable=false)
     */
    protected $password;
    /**
     * @ORMColumn(type="datetime", nullable=true)
     */
    protected $created_at;
    /**
     * @ORMColumn(type="datetime", nullable=true)
     */
    protected $updated_at;
    ...
}

图像

namespace AppModels;
use DoctrineORMMapping as ORM;
use SymfonyComponentValidatorConstraints as Assert;
/**
 * @ORMEntity
 * @ORMTable(name="images")
 * @ORMHasLifecycleCallbacks
 */
class Image {
    /**
     * @ORMId
     * @ORMColumn(type="integer")
     * @ORMGeneratedValue
     */
    protected $id;
    /**
     * @ORMManyToOne(targetEntity="AppModelsUser")
     * @ORMJoinColumn(name="user_id", referencedColumnName="id")
     */
    protected $user_id;
    /**
     * @ORMColumn(type="datetime", nullable=true)
     */
    protected $created_at;
    /**
     * @ORMColumn(type="datetime", nullable=true)
     */
    protected $updated_at;
    /**
     * @ORMColumn(type="string", nullable=false)
     */
    protected $location;
    /**
     * @ORMColumn(type="integer", nullable=false)
     */
    protected $imageSize;
    ....
}

当我运行'vendorbindoctrine' migrations:diff时，它会继续并生成迁移。虽然只是一次迁移...

迁移

namespace ImageUplaoderMigrations;
use DoctrineDBALMigrationsAbstractMigration;
use DoctrineDBALSchemaSchema;
/**
 * Auto-generated Migration: Please modify to your needs!
 */
class Version20150430210959 extends AbstractMigration
{
    /**
     * @param Schema $schema
     */
    public function up(Schema $schema)
    {
        // this up() migration is auto-generated, please modify it to your needs
        $this->abortIf($this->connection->getDatabasePlatform()->getName() != 'mysql', 'Migration can only be executed safely on 'mysql'.');
        $this->addSql('CREATE TABLE images (id INT AUTO_INCREMENT NOT NULL, user_id INT DEFAULT NULL, created_at DATETIME DEFAULT NULL, updated_at DATETIME DEFAULT NULL, location VARCHAR(255) NOT NULL, imageSize INT NOT NULL, INDEX IDX_E01FBE6AA76ED395 (user_id), PRIMARY KEY(id)) DEFAULT CHARACTER SET utf8 COLLATE utf8_unicode_ci ENGINE = InnoDB');
        $this->addSql('CREATE TABLE users (id INT AUTO_INCREMENT NOT NULL, firstName VARCHAR(32) NOT NULL, lastName VARCHAR(32) NOT NULL, userName VARCHAR(100) NOT NULL, email VARCHAR(100) NOT NULL, password VARCHAR(500) NOT NULL, created_at DATETIME DEFAULT NULL, updated_at DATETIME DEFAULT NULL, UNIQUE INDEX UNIQ_1483A5E9586CA949 (userName), UNIQUE INDEX UNIQ_1483A5E9E7927C74 (email), PRIMARY KEY(id)) DEFAULT CHARACTER SET utf8 COLLATE utf8_unicode_ci ENGINE = InnoDB');
        $this->addSql('ALTER TABLE images ADD CONSTRAINT FK_E01FBE6AA76ED395 FOREIGN KEY (user_id) REFERENCES users (id)');
    }
    /**
     * @param Schema $schema
     */
    public function down(Schema $schema)
    {
        // this down() migration is auto-generated, please modify it to your needs
        $this->abortIf($this->connection->getDatabasePlatform()->getName() != 'mysql', 'Migration can only be executed safely on 'mysql'.');
        $this->addSql('ALTER TABLE images DROP FOREIGN KEY FK_E01FBE6AA76ED395');
        $this->addSql('DROP TABLE images');
        $this->addSql('DROP TABLE users');
    }
}

这不是我想要

的，我想要个人迁移。我不能一次创建多个实体，然后运行某种命令来生成彼此独立的迁移吗？

Answer 1

首先，迁移工具只是一个工具。它不是从版本生成路径的防弹方式。通常，它用作您将手动修改的模板。

具体回答您的问题，因为该工具旨在比较整体架构。考虑到实体之间存在关系，无论如何都不可能评估单个实体。

不过，我真的不明白您想要拆分迁移的原因。通常，这是一个全有或全无的交易，因为您的应用程序期待一个单一版本（除非您的应用程序真的很聪明！

长话短说，它只是一个开发人员工具，而不是您问题的解决方案。