我也为Scrollview(8images)+工具栏编写了代码。当我尝试单击工具栏按钮项时,滚动视图没有按预期返回。下面是代码。
当我单击工具栏按钮时,没有触发"IBAction clickprjinfo"的操作,我已经通过连接检查器中的 Barbuttonitem 确认对此 IBACTION 执行了"发送操作"。
在运行时,当我单击按住工具栏按钮 + 触摸 ScroolView 屏幕 + 然后释放按钮时,它会触发 IBACTION。
任何人都可以帮助通知我的错误或更好的方法来理解这一点。
-(void)viewDidLoad
{
[super viewDidLoad];
[self pgcontrolview];
}
-(void) pgcontrolview {
pageC.numberOfPages=8;
pageC.currentPage=0;
for (int i=1; i<=8; i++)
{
UIImageView *images=[[UIImageView alloc]initWithImage:[UIImage imageNamed:[NSString stringWithFormat:@"%d.jpg",i]]];
images.frame=CGRectMake((i-1)*1024, 0, 1024, 760);
[scroller addSubview:images];
}
scroller.delegate=self;
scroller.contentSize=CGSizeMake(1024*8, 760);
scroller.pagingEnabled=YES;
UITapGestureRecognizer *tap = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(handle_Tap:)];
tap.numberOfTapsRequired = 1;
tap.numberOfTouchesRequired = 1;
[self.view addGestureRecognizer:tap];
}
-(IBAction)clickprjinfo:(id)sender{
pageC.currentPage=1;
CGRect frame=scroller.frame;
frame.origin.x=0;//frame.size.width*page;
frame.origin.y=0;
[scroller scrollRectToVisible:frame animated:YES];
}
添加手势委托方法,如下所示
- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch {
// test if our control subview is on-screen
if ([touch.view isKindOfClass:[UIControl class]]) {
// we touched a button, slider, or other UIControl
return NO; // ignore the touch
}
return YES; // handle the touch
}
因为它将UIButton点击视为UITapGesture,所以你不需要允许UIButton上的UITapGesture,因为上面的委托方法忽略了UIControl上的触摸(反过来UIButton)作为允许执行
-(IBAction)clickprjinfo:(id)sender
行动