C# JSON 匿名序列化

Question

我正在尝试为API调用序列化一些JSON：

string f5Name = "MyBigIpName";
string poolName = "myPoolName";
string postJson2 = JsonConvert.SerializeObject(
    new
    {
        f5 = new {
            f5Name = new {
                poolName = memberState
            },
        }
    }
);

这将生成以下 JSON：

{
    "f5": {
        "f5Name": {
            "poolName": {
                "member": {
                    "address": "10.0.0.0",
                    "port": 80
                },
                "session_state": "STATE_DISABLED"
            }
        }
    }
}

但是，我真正想做的是生成此 JSON：

{
    "f5": {
        "MyBigIpName": {
            "myPoolName": {
                "member": {
                    "address": "10.0.0.0",
                    "port": 80
                },
                "session_state": "STATE_DISABLED"
            }
        }
    }
}

有没有办法让 f5Name 和 poolName 属性名称是动态的，以便我可以生成上述 JSON？ 我正在使用Newtonsoft.JSON （JSON.NET）

Answer 1

我不确定您是否可以使用dynamic类型做某事，但您肯定可以使用字典做一些事情：

var obj = new
{
    f5 = new Dictionary<string, object>
    {
        {
            f5Name, new Dictionary<string, object> {
                {poolName, memberState}
            }
        }
    }
}
string postJson2 = JsonConvert.SerializeObject(obj);

Answer 2

对于您的意图，您需要在合约解析器中解析您的姓名。像这样：

private class MyContractResolver : DefaultContractResolver
{
  private Dictionary<string,string> _translate;
  public MyContractResolver(Dictionary<string, string> translate)
  {
    _translate = translate;
  }
  protected override JsonProperty CreateProperty(MemberInfo member, MemberSerialization memberSerialization)
  {
    var property = base.CreateProperty(member, memberSerialization);
    string newPropertyName;
    if(_translate.TryGetValue(property.PropertyName, out newPropertyName))
      property.PropertyName = newPropertyName;
    return property;
  }
}

然后：

string f5Name = "MyBigIpName";
string poolName = "MyPoolName";     
var _translator = new Dictionary<string, string>()
{
  { "f5Name", f5Name },
  { "poolName", poolName },
};
string postJson2 = JsonConvert.SerializeObject(
    new
    {
      f5 = new {
        f5Name = new {
            poolName = memberState
        },
    },
    new JsonSerializerSettings { ContractResolver = new MyContractResolver(_translator) });

如果使用 C# 6，则可以从nameof中受益和/或使用字典初始化器使其更干净：

var _translator = new Dictionary<string, string>()
{
  [nameof(f5Name)] = f5Name ,
  [nameof(poolName)] = poolName ,
};

字典创建过程也可以轻松自动化：-）