如何使用subprocess.call拦截来自Python shell exec的stdout

Question

我想创建一个将返回 shell 输出的函数，我有这样的东西：

def shell_exec(code):
    buff = StringIO.StringIO()
    subprocess.call(code, shell=True, stdout=buff)
    return buff.getvalue()

但出现错误：

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "<stdin>", line 3, in shell_exec
  File "/usr/lib/python2.7/subprocess.py", line 524, in call
    return Popen(*popenargs, **kwargs).wait()
  File "/usr/lib/python2.7/subprocess.py", line 703, in __init__
    errread, errwrite) = self._get_handles(stdin, stdout, stderr)
  File "/usr/lib/python2.7/subprocess.py", line 1115, in _get_handles
    c2pwrite = stdout.fileno()
AttributeError: StringIO instance has no attribute 'fileno'

Answer 1

使用 subprocess.check_output .它返回命令输出。

def shell_exec(code):
    try:
        return subprocess.check_output(code, shell=True)
    except subprocess.CalledProcessError as e:
        return e.output

顺便说一句，stdin、stdout、stderr的有效值是PIPE、DEVNULL、现有文件描述符（正整数）、现有文件对象和None。