尝试编写便利性toString()
方法,列出了对象的所有属性及其分配的值。
class FooModel
{
func toString() -> String
{
var result = "[(String(describing: type(of: self))) "
let mirror = Mirror(reflecting: self)
mirror.children.forEach
{
child in
result += "(child.label): (child.value), "
}
return "(result)]"
}
}
class FooProject : FooModel
{
var id = 0
var name = ""
var announcement:String?
var showAnnouncement = false
var isCompleted = false
var completedOn:String?
var suiteMode = 0
var url = ""
}
输出:
[FooProject Optional("id"): 0, Optional("name"): , Optional("announcement"): nil, Optional("showAnnouncement"): false, Optional("isCompleted"): false, Optional("completedOn"): nil, Optional("suiteMode"): 0, Optional("url"): , ]
首先,它没有列出实际值,而是默认值。这是为什么?其次,有没有办法摆脱Optional
封装?
根据有关Child
的文档:
儿童
反射实例结构的元素。可以在适当的情况下使用可选标签,例如代表一个名称 存储的属性或活动枚举案例,将用于查找 当字符串传递给后代方法时。
因为镜子中的类型儿童被定义为
typealias Child = (label: String?, value: Any)
因此,所有名称均被打印为选项。
要获取可以使用可选绑定
的标签名称我进行了一些更改,并在操场上尝试了此操作:
class FooModel
{
func toString() -> String
{
var result = "[(String(describing: type(of: self))) "
let mirror = Mirror(reflecting: self)
mirror.children.forEach
{
child in
print(child)
if let label = child.label {
result += "(label): (child.value), "
}
}
return "(result)]"
}
}
class FooProject : FooModel
{
var id = 0
var name = ""
var announcement:String!
var showAnnouncement = false
var isCompleted = false
var completedOn:String!
var suiteMode = 0
var url = ""
init(id: Int, name: String, completedOn: String) {
self.completedOn = completedOn
self.id = id
self.name = name
//...
}
}
let fooProj = FooProject(id: 10, name: "Name", completedOn: "Sunday")
print(fooProj.toString())
ouptut是:
[FooProject id: 10, name: Name, announcement: nil, showAnnouncement: false, isCompleted: false, completedOn: Sunday, suiteMode: 0, url: , ]
hth ..