如何添加多次单击后按下按钮

Question

如何添加多个背面按钮，例如按下向后按钮显示我在吐司消息后单击double单击时，当我单击double on Perspers on Perspert按钮，然后应用程序退出...我做过这种方法，但它只是两次退出我想实现3次应用的应用程序

    if (doubleBackToExitPressedOnce){
        super.onBackPressed();
        doubleBackToExitPressedOnce = false;
    }
    else {
        doubleBackToExitPressedOnce = true;
        Toast.makeText(this, "Double Press to exit", Toast.LENGTH_SHORT).show();
    }

Answer 1

我建议这样：

    int counter = 0;

    ....
    public void onBackPressed() {
                        counter++;
                        if(counter > 2){
                            System.exit(0);
                        }else{
                            Toast.makeText(this, "TRIPLE CLICK TO EXIT!", Toast.LENGTH_SHORT).show();  
                        }
                        final long DELAY_TIME = 3000L;
                        new Thread(new Runnable() {
                            public void run(){
                                try {
                                    Thread.sleep(DELAY_TIME);
                                    counter = 0;
                                } catch (InterruptedException e) {
                                    e.printStackTrace();
                                }
                            }
                        }).start();
}

Answer 2

从UI的角度看，这似乎超级骇客，但是如果您真的想这样做，那么一种简单的方法可能是：

Integer backToExitPressedCounter = 0
...
if(backToExitPressedCounter==3){
    super.onBackPressed();
    backToExitPressedCounter = 0;
} else {
    backToExitPressedCounter++;
    Toast.makeText(this, "Triple Press to exit", Toast.LENGTH_SHORT).show();
}