@jacksonxmlproperty(isAttribute = true)使用Jackson XMLMAPPER附加

Question

嗨，我正在尝试使用jackson-dataformat-xml 2.7.3 xmlmapper将我的pojo转换为XML。我正在使用以下代码中给出的POJO类中的Jackson注释，但是我会在列表的每个标签中获得一些唯一的ID。我如何删除这些唯一的ID。

//以下是 elementTag类

import java.util.List;
import 
com.fasterxml.jackson.dataformat.xml.annotation.JacksonXmlElementWrapper;
import com.fasterxml.jackson.dataformat.xml.annotation.JacksonXmlProperty;
/**
*Element class
*/
public class ElementTag {
@JacksonXmlProperty(localName = "FL")
@JacksonXmlElementWrapper(useWrapping = false)
private List<ProfessionalLeadDetails> pf;
/**
 * @return the pf
 */
public List<ProfessionalLeadDetails> getPf() {
    return pf;
}
/**
 * @param pf the pf to set
 */
public void setPf(List<ProfessionalLeadDetails> pf) {
    this.pf = pf;
}   
}

//以下是 prinessivealleaddetails class

import java.io.Serializable;
import com.fasterxml.jackson.annotation.JsonIgnoreProperties;
import com.fasterxml.jackson.dataformat.xml.annotation.JacksonXmlProperty;

public class ProfessionalLeadDetails implements Serializable {
/** The Constant serialVersionUID. */
private static final long serialVersionUID = 1L;

@JacksonXmlProperty(isAttribute = true)
 private String val;
 private String value;
    /**
 * @return the val
 */
public String getVal() {
    return val;
}
/**
 * @param val the val to set
 */
public void setVal(String val) {
    this.val = val;
}
/**
 * @return the value
 */
public String getValue() {
    return value;
}
/**
 * @param value the value to set
 */
public void setValue(String value) {
    this.value = value;
}
}

//使用XMLMAPPER在MAIN MEDATEN内部使用XMLMAPPER转换为XML

XmlMapper xmlMapper = new XmlMapper();
    ElementTag et = new ElementTag();
    List<ProfessionalLeadDetails> pfList = new 
ArrayList<ProfessionalLeadDetails>();
    ProfessionalLeadDetails pf = new ProfessionalLeadDetails();
    pf.setVal("First Name");
    pf.setValue("Sandeep");
    pfList.add(pf);
    pf = new ProfessionalLeadDetails();
    pf.setVal("Email");
    pf.setValue("[e-mail]");
    pfList.add(pf);
    pfList.add(pf2);
    et.setPf(pfList);
    try {
System.out.println(xmlMapper.writer()
.with(SerializationFeature.WRAP_ROOT_VALUE)
            .withRootName("Leads").writeValueAsString(et));
} catch (JsonProcessingException e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
}

但是我在val之前得到了一些唯一的ID，例如ZDEF1999262822：如下所示：输出

  <Leads xmlns=""><FL zdef2041716767:val="First Name"><value>Sandeep</value></FL><FL zdef1999262822:val="Email"><value>[e-mail]</value></FL></Leads>

所需的输出：

 <Leads xmlns=""><FL val="First Name"><value>Sandeep</value></FL><FL val="Email"><value>[e-mail]</value></FL></Leads>

预先感谢！

Answer 1

确保使用woodstox stax实现，而不是与JDK使用的STAX实现Oracle捆绑包。这通常是通过添加Maven依赖性来明确包含Woodstox Jar来完成的。这在XML模块上进行了解释

<dependency>
          <groupId>org.codehaus.woodstox</groupId>
          <artifactId>woodstox-core-asl</artifactId>
          <version>4.4.1</version>
        </dependency>