嘿,伙计们一个快速的应用程序,该应用程序通过帖子获取文件,并且应该保存它,将其发送到另一台服务器并之后将其删除。整个过程都有效,但是如果我记录了程序制成的步骤。因此,目前,我想知道是否有可能逐步调用3个函数。因为在保存之前删除文件不正确。所以这是我的代码,希望您可以帮助我。
server.post("/upload", function (req, res) {
if (!req.files) {
res.send("No file uploaded");
} else {
//the Filepointer points to the whole File object which can contain multiple files
var filePointer = req.files;
console.log(filePointer);
res.send("Files uploaded");
let key;
for (key of Object.keys(filePointer)) {
//single file uploaded so no json Object else get number of elements in the Array and loop over them
if ((typeof filePointer[key][0]) === 'undefined') {
//if theres only one File in the Object you can directly access the keys
var file = filePointer[key];
//console.log("var is undefined");
console.log(file["name"]);
var uploadPath = __dirname + "/uploads/" + file["name"];
console.log(uploadPath);
saveFile(uploadPath, file);
sendToTika();
deleteFile(uploadPath);
} else {
let index;
for (index of Object.keys(filePointer[key])) {
//with multiple files you need to access the keys with an indey i
var file = filePointer[key][index];
console.log(file["name"]);
var uploadPath = __dirname + "/uploads/" + file["name"];
console.log(uploadPath);
saveFile(uploadPath, file);
sendToTika();
deleteFile(uploadPath);
}
}
}
}
});
server.listen(3000, function () {
console.log("server is listening on port 3000");
})
function saveFile(UploadPath, file) {
file.mv(UploadPath, function (err) {
if (err) {
console.log(err);
} else {
console.log("file uploaded and saved" + UploadPath);
}
})
}
function sendToTika() {
console.log("tika Function");
}
//TODO: check if sync or async is better for this task
function deleteFile(deletePath) {
fs.unlink(deletePath, function (error) {
if (error) {
console.log(error);
}
console.log("deleted" + deletePath);
})
}
控制台日志是:
tika Function
deleted
file uploaded and saved
编辑:嘿,首先,谢谢大家的回答,我会看看诺言!
尝试此
function saveFile(UploadPath, file) {
return new Promise(function(resolve, reject) {
file.mv(UploadPath, function (err) {
if (err) {
reject(err);
console.log(err);
} else {
resolve(true);
console.log("file uploaded and saved" + UploadPath);
}
});
});
}
function deleteFile(deletePath) {
return new Promise(function (resolve, reject) {
fs.unlink(deletePath, function (error) {
if (error) {
reject(error);
console.log(error);
}
else {
resolve(true);
console.log("deleted" + deletePath);
}
});
});
}
最后,
router.post('/upload', function(req, response){
saveFile(uploadPath, file).then((status) => {
if(status){
sendToTika().then((result) => {
if(result){
deleteFile(uploadPath);
response.send({"status": true, "error": ''}) ;
}
else
response.sendStatus(203);
}).catch((err) => {
response.sendStatus(203);
})
}
else
response.sendStatus(203);
}).catch((err) => {
response.sendStatus(203);
})
});
我希望这对您有帮助。
问题是函数saveFile
和deleteFile
使用异步函数(回调)您可以使用Promise
:
function saveFile(UploadPath, file) {
return new Promise(function(resolve, reject) {
file.mv(UploadPath, function (err) {
if (err) {
reject(err);
console.log(err);
} else {
resolve();
console.log("file uploaded and saved" + UploadPath);
}
});
});
}
function deleteFile(deletePath) {
return new Promise(function (resolve, reject) {
fs.unlink(deletePath, function (error) {
if (error) {
reject(error);
console.log(error);
}
else {
resolve();
console.log("deleted" + deletePath);
}
});
});
}
使用相同的逻辑作为sendToTika
函数,然后以这样的方式调用函数:
saveFile(uploadPath, file).then(() => {
return sendToTika();
}).then(() => {
return deleteFile(uploadPath);
}).catch((err) => {
// get the error here
})
您还可以使用函数 util.promisify
返回返回承诺的函数版本:https://nodejs.org/api/util.html#util_util_util_util_promisify_original_original