如何解析 json 数组 json.net

Question

我知道这听起来很基本，但围绕这个问题的所有答案都是愚蠢的大而笨重的代码，不允许我需要的功能。 我需要解析这个 JSON 数组。

[
   {
      "label":"Cow (1)",
      "value":3309
   },
   {
      "label":"Cow (1)",
      "value":14998
   },
   {
      "label":"Cow (4)",
      "value":20969
   },
   {
      "label":"Cow (4)",
      "value":20970
   },
   {
      "label":"Cow (4)",
      "value":20971
   },
   {
      "label":"Cowardly Bandit",
      "value":1886
   },
   {
      "label":"Cow calf (1)",
      "value":2310
   },
   {
      "label":"Coward in armour (82)",
      "value":5097
   },
   {
      "label":"Coward with bow (105)",
      "value":6049
   },
   {
      "label":"Cow calf (1)",
      "value":20979
   },
   {
      "label":"Undead cow (4)",
      "value":1691
   },
   {
      "label":"Plague cow",
      "value":1998
   },
   {
      "label":"Plague cow",
      "value":1999
   },
   {
      "label":"Unicow (57)",
      "value":5603
   },
   {
      "label":"Zombie cow (1)",
      "value":18597
   },
   {
      "label":"Zombie cow (1)",
      "value":20928
   },
   {
      "label":"Super Cow (5)",
      "value":21497
   },
   {
      "label":"Dairy cow",
      "value":22418
   },
   {
      "label":"Armoured cow thing (62)",
      "value":5986
   },
   {
      "label":"Armoured cow thing (62)",
      "value":6048
   }
]

当我尝试访问数组内的数据点时，它会返回 null，代码：

Stream stream = client.OpenRead("http://services.runescape.com/m=itemdb_rs/bestiary/beastSearch.json?term=" + Input);
StreamReader reader = new StreamReader(stream);
jObject = JObject.Parse(reader.ReadToEnd());
stream.Close();
//put items into list view
// i is the number where the json object is in the array 
var lvi = new ListViewItem(new string[] { (string)jObject[i]["label"], (string)jObject[i]["value"] }); 

我不想使用类

Answer 1

在代码中发现错误。相反：

JObject.Parse(reader.ReadToEnd());

写（JObject -> JArray）：

string text = reader.ReadToEnd();
var jObject = JArray.Parse(text);

同样，当在 2 行中执行写入操作时，您将看到错误所在：从流中读取或序列化。

Answer 2

不想使用类很奇怪，但并非不可能。

var json = reader.ReadToEnd();
var objects = JsonConvert.DeserializeObject<dynamic[]>(json);
var lvi = new ListViewItem(new string[] { (string)objects[i].label, (string)objects[i].value }); 

Answer 3

试试我对这个问题的回答：

public IEnumerable<MeItem> DeserializeListFromJson(string jsonArray)
{
    return JsonConverter.DeserializeObject<List<JObject>>(jsonArray).Select( obj => DeserializeFromJson(obj) );
}
public MeItem DeserializeFromJson(string jsonString)
{
    return JsonConvert.DeserializeObject<MeItem>(jsonString);
}

您可以在我对此问题和此问题的回答中找到必要的详细信息

编辑：

如果你不想使用类，那么你可以DeserializeFromJson()方法修改为这样的东西：

public KeyValuePair<string, string> DeserializeFromJson(JObject obj)
{
    return new KeyValuePair<string, string>(obj.SelectToken("label").Value<string>(), obj.SelectToken("value").Value<string>());
}

这将需要DeserializeListFromJson()方法修改为：

public IEnumerable<KeyValuePair<string,string>> DeserializeListFromJson(string jsonArray)
{
    return JsonConverter.DeserializeObject<List<JObject>>(jsonArray).Select( obj => DeserializeFromJson(obj) );
}

与您的案例一起使用 ：

Stream stream = client.OpenRead("http://services.runescape.com/m=itemdb_rs/bestiary/beastSearch.json?term=" + Input);
ListViewItem item = null;
using (StreamReader reader = new StreamReader(stream))
{
    KeyValuePair<string, string> selected = DeserializeListFromJson(reader.ReadToEnd()).ElementAt(i);
    item = new ListViewItem(new string[] { selected.Key, selected.Value });
}