时。
在url编码的json中有许多电子邮件地址，与它们的角色一起发送。像这样:
hl=en_US&token=AFNOsBbXXvng6zJmmPyIlya1dT48RKqmaQ%3A1441100947178&foreignService=explorer&shareService=explorer&authuser=0&locale=en_US&requestType=aclChange&itemIds=0B-i4kCZeNb05Y3FrVXFLYU41N0U&confirmed=false&modelChanges=%7B%22aclEntries%22%3A%5B%7B%22scope%22%3A%7B%22scopeType%22%3A%22user%22%2C%22name%22%3A%22babar.memon%40gmail.com%22%2C%22id%22%3A%22112542596153041291285%22%2C%22me%22%3Afalse%2C%22requiresKey%22%3Afalse%2C%22email%22%3A%22babar.memon%40gmail.co%22%7D%2C%22role%22%3A30%7D%2C%7B%22scope%22%3A%7B%22iconUrl%22%3A%22%2Fc%2Fu%2F0%2Fphotos%2Fpublic%2FAIbEiAIAAABDCL_k77OCsqvJPSILdmNhcmRfcGhvdG8qKGM0MmEwMjBkZWQ0MDAzMzMwYjI2MjczZmNlZWVlMDA3NDUxMGI2N2MwAdau5OHbez_zFcRyTELkBcRF-Lv9%22%2C%22scopeType%22%3A%22user%22%2C%22name%22%3A%22Saad%20Rehman%22%2C%22id%22%3A%22104436799417545912895%22%2C%22me%22%3Afalse%2C%22requiresKey%22%3Afalse%2C%22email%22%3A%22this.saad%40gmail.com%22%7D%2C%22role%22%3A20%7D%2C%7B%22scope%22%3A%7B%22iconUrl%22%3A%22%2Fc%2Fu%2F0%2Fphotos%2Fpublic%2FAIbEiAIAAABDCL_k77OCsqvJPSILdmNhcmRfcGhvdG8qKGM0MmEwMjBkZWQ0MDAzMzMwYjI2MjczZmNlZWVlMDA3NDUxMGI2N2MwAdau5OHbez_zFcRyTELkBcRF-Lv9%22%2C%22scopeType%22%3A%22user%22%2C%22name%22%3A%22Saad%20Rehman%22%2C%22id%22%3A%22104436799417545912895%22%2C%22me%22%3Afalse%2C%22requiresKey%22%3Afalse%2C%22email%22%3A%22this.saad%40gmail.com%22%7D%2C%22role%22%3A60%7D%2C%7B%22scope%22%3A%7B%22scopeType%22%3A%22user%22%2C%22name%22%3A%22Asim%20Kazmi%22%2C%22id%22%3A%22118161687853857289891%22%2C%22me%22%3Afalse%2C%22requiresKey%22%3Afalse%2C%22email%22%3A%22asim.kazmi%40elasticaqa.info%22%7D%2C%22role%22%3A20%7D%2C%7B%22scope%22%3A%7B%22scopeType%22%3A%22user%22%2C%22name%22%3A%22Asim%20Kazmi%22%2C%22id%22%3A%22118161687853857289891%22%2C%22me%22%3Afalse%2C%22requiresKey%22%3Afalse%2C%22email%22%3A%22asim.kazmi%40elasticaqa.info%22%7D%2C%22role%22%3A60%7D%5D%7D
如果我只想要旁边角色为30的电子邮件地址，或者在另一个规则中，旁边角色为20的所有电子邮件地址，该怎么办?
这是我目前所做的:'
.*?email.22.3A.22([a-zA-Z0-9_.+%-]+?%40[a-zA-Z0-9_%-]+?[.][a-zA-Z0-9_.%-]+?).22[^r]+role.22.3A30.7D
这应该给我所有的电子邮件地址有角色30旁边，即babar.memon%40elastica.com。如果我把.0放在30的位置，那么我就会得到所有的电子邮件地址，就像我想要的那样，除了我想要它们分开，首先是角色30的所有电子邮件地址，然后是角色20等。
这个正则表达式可以在这里找到https://regex101.com/r/rW0qO9/1
Regex可以用于从字符串中提取模式，但您不能按特定顺序提取它们，因为每个匹配都是示例字符串的子字符串。你必须在后期收集这些火柴并订购它们。
还有一种可能性，您通过参数化(.0)部分(在您的regex中)与20和30和40动态地构建您的regex，通过取一个变量并逐个提取它们。
试试这个正则表达式.*?email.22.3A.22([a-zA-Z0-9_.+-]+?%40[a-zA-Z0-9_%-]+?[.][a-zA-Z0-9_.-]+).22[^r]+role.22.3A(20).7D，我稍微改变了捕获组，因为在电子邮件地址中我们不能有像%这样的特殊字符，所以它只会出现在'@'编码为%40