我的条件不起作用,我是初学者程序员


double a = 10;// the 10 dollars to spend
double b = 0;// the cost of he food
double c;// final total
double d;// amount of sandwiches
c = a-b;
String Order;
Scanner sc = new Scanner(System.in);

这就是我试图做的,我的目标是得到三明治的数量并乘以它;当数字是2或更低时,她说一件事3或更高。问题是它要求我将变量初始化为 0,但显然 d*0 仍然为零。

System.out.println("That'll be 1.06 how many would you like?");
b = 1.06*d;
d = sc.nextDouble();
System.out.println(d <= 2 ?"Ok! Coming right up Sir!":"...Ok.... she     probably thinks you're a fatso now.");
System.out.println("She hands you back "+(a-b)+" as your change");
break;

问题就在这里:

System.out.println("That'll be 1.06 how many would you like?");
b = 1.06*d;
d = sc.nextDouble();

你还没有初始化d,所以当你做乘法时,你什么都没有乘法。您需要先将扫描仪的值加载到d中,然后再乘以b

System.out.println("That'll be 1.06 how many would you like?");
d = sc.nextDouble();
b = 1.06*d;

交换作业的顺序。

b = 1.06*d; // <-- what's d?
d = sc.nextDouble();

喜欢

d = sc.nextDouble();
b = 1.06 * d;

此外,您应该选择更有意义的变量名称。

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