这是我的请求:
<v:Envelope xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns:d="http://www.w3.org/2001/XMLSchema" xmlns:c="http://schemas.xmlsoap.org/soap/encoding/" xmlns:v="http://schemas.xmlsoap.org/soap/envelope/">
<v:Body>
<insertBeacons xmlns="http://tempuri.org/insertBeacons/">
<MAC_ADDRESS>gmg</MAC_ADDRESS>
<UUID>gmg</UUID>
<MAJOR>gmg</MAJOR>
<MINOR>gmg</MINOR>
<MEASURED_POWER>gmg</MEASURED_POWER>
<RSSI>rssi ejemplo</RSSI>
</insertBeacons>
</v:Body>
</v:Envelope>
我需要像这样发送
<soap:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">
<soap:Body>
<insertBeacons xmlns="http://tempuri.org/">
<MAC_ADDRESS>string</MAC_ADDRESS>
<UUID>string</UUID>
<MAJOR>string</MAJOR>
<MINOR>string</MINOR>
<MEASURED_POWER>string</MEASURED_POWER>
<RSSI>string</RSSI>
</insertBeacons>
</soap:Body>
</soap:Envelope>
您可以看到,在我的请求中,我的服务需要"肥皂"字。
任何人都可以帮助。
很高兴您问了这个问题,当我开始使用SOAP WebService时,我遇到了同样的问题。这里的关键是避免使用SOAP库,然后去Java提供的课程来提出请求并解析,即HTTP,DOM Parser或SAX Parser。这就是您在不使用KSOAP或任何其他库的情况下提出请求的方式。
现在进入Androiod代码:
我们将创建一个名为Runtask的类,该类别扩展异步任务并使用HTTP发送请求正文并获取请求响应:
private class runTask extends AsyncTask<String, String, String> {
private String response;
String string = "your string parameter"
String SOAP_ACTION = "your soap action here";
String stringUrl = "http://your_url_here";
//if you experience a problem with url remove the '?wsdl' ending
@Override
protected String doInBackground(String... params) {
try {
//paste your request structure here as the String body.
String body = "<soap:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">"+
"<soap:Body>"+
"<insertBeacons xmlns="http://tempuri.org/">"+
"<MAC_ADDRESS>"+string+"</MAC_ADDRESS>"+
"<UUID>"+string+"</UUID>"+
"<MAJOR>"+string+"</MAJOR>"+
"<MINOR>"+string+"</MINOR>"+
"<MEASURED_POWER>"+string+"</MEASURED_POWER>"+
"<RSSI>"+string+"</RSSI>"+
"</insertBeacons>"+
"</soap:Body>"+
"</soap:Envelope>";
try {
URL url = new URL(stringUrl);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("POST");
conn.setDoOutput(true);
conn.setDefaultUseCaches(false);
conn.setRequestProperty("Accept", "text/xml");
conn.setRequestProperty("SOAPAction", SOAP_ACTION);
//you can pass all your request parameters here usong .setRequestProperty() method
//push the request to the server address
OutputStreamWriter wr = new OutputStreamWriter(conn.getOutputStream());
wr.write(body);
wr.flush();
//get the server response
BufferedReader reader = new BufferedReader(new InputStreamReader(conn.getInputStream()));
StringBuilder builder = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
builder.append(line);
response = builder.toString();//this is the response, parse it in onPostExecute
}
} catch (Exception e) {
e.printStackTrace();
} finally {
try {
reader.close();
} catch (Exception e) {
e.printStackTrace();
}
}
} catch (Exception e) {
e.printStackTrace();
}
return response;
}
/**
* @see AsyncTask#onPostExecute(Object)
*/
@Override
protected void onPostExecute(String result) {
try {
Toast.makeText(this,"Response "+ result,Toast.LENGTH_LONG).show();
//Go ahead and parse the response now
} catch (Exception e) {
e.printStackTrace();
}
}
现在,在您的创建中,只需继续使用以下代码
执行此类runTask task = new runTask();
task.execute();
您将在OnPostexecute,格式化并从这里分析它。使用此无库方式的主要优点是它是灵活的,您可以以任何仅使用提供的请求格式的库以任何方式格式化请求。该解决方案在我的代码中无缝工作,随时要求进一步澄清。