我如何使用phpspreadsheet(新版本的phpexcel(，但没有安装作曲家。
我试图与thirt_party一起使用，但要打印出这样的错误：
"致命错误：类'phpoffice phpspreadsheet 电子表格'在/web/application/third_party/phpoffice/phpoffice/phpspreadsheet/spreadsheet/spreadsheet.php中，在第16行16"
(€ayudaaaa！
这是我使用的类：(我对此进行了一些修改(
<?php
if (!defined('BASEPATH')) {
exit('No direct script access allowed');
}
/**
* An example of a general-purpose implementation that includes the optional
* functionality of allowing multiple base directories for a single namespace
* prefix.
*
* Given a foo-bar package of classes in the file system at the following
* paths ...
*
* /path/to/packages/foo-bar/
* src/
* Baz.php # FooBarBaz
* Qux/
* Quux.php # FooBarQuxQuux
* tests/
* BazTest.php # FooBarBazTest
* Qux/
* QuuxTest.php # FooBarQuxQuuxTest
*
* ... add the path to the class files for the FooBar namespace prefix
* as follows:
*
* <?php
* // instantiate the loader
* $loader = new Exampleautoloader_psr4;
*
* // register the autoloader
* $loader->register();
*
* // register the base directories for the namespace prefix
* $loader->addNamespace('FooBar', '/path/to/packages/foo-bar/src');
* $loader->addNamespace('FooBar', '/path/to/packages/foo-bar/tests');
*
* The following line would cause the autoloader to attempt to load the
* FooBarQuxQuux class from /path/to/packages/foo-bar/src/Qux/Quux.php:
*
* <?php
* new FooBarQuxQuux;
*
* The following line would cause the autoloader to attempt to load the
* FooBarQuxQuuxTest class from /path/to/packages/foo-bar/tests/Qux/QuuxTest.php:
*
* <?php
* new FooBarQuxQuuxTest;
*/
class autoloader_psr4
{
/**
* An associative array where the key is a namespace prefix and the value
* is an array of base directories for classes in that namespace.
*
* @var array
*/
protected $prefixes = array();
/**
* Register loader with SPL autoloader stack.
*
* @return void
*/
public function register()
{
spl_autoload_register(array($this, 'loadClass'));
}
/**
* Adds a base directory for a namespace prefix.
*
* @param string $prefix The namespace prefix.
* @param string $base_dir A base directory for class files in the
* namespace.
* @param bool $prepend If true, prepend the base directory to the stack
* instead of appending it; this causes it to be searched first rather
* than last.
* @return void
*/
public function addNamespace($prefix, $base_dir, $prepend = false)
{
// normalize namespace prefix
$prefix = trim($prefix, '\') . '\';
// normalize the base directory with a trailing separator
$base_dir = rtrim($base_dir, DIRECTORY_SEPARATOR) . '/';
// initialize the namespace prefix array
if (isset($this->prefixes[$prefix]) === false) {
$this->prefixes[$prefix] = array();
}
// retain the base directory for the namespace prefix
if ($prepend) {
array_unshift($this->prefixes[$prefix], $base_dir);
} else {
array_push($this->prefixes[$prefix], $base_dir);
}
}
/**
* Loads the class file for a given class name.
*
* @param string $class The fully-qualified class name.
* @return mixed The mapped file name on success, or boolean false on
* failure.
*/
public function loadClass($class)
{
// the current namespace prefix
$prefix = $class;
// work backwards through the namespace names of the fully-qualified
// class name to find a mapped file name
while (false !== $pos = strrpos($prefix, '\')) {
// retain the trailing namespace separator in the prefix
$prefix = substr($class, 0, $pos + 1);
// the rest is the relative class name
$relative_class = substr($class, $pos + 1);
// try to load a mapped file for the prefix and relative class
$mapped_file = $this->loadMappedFile($prefix, $relative_class);
if ($mapped_file) {
return $mapped_file;
}
// remove the trailing namespace separator for the next iteration
// of strrpos()
$prefix = rtrim($prefix, '\');
}
// never found a mapped file
return false;
}
/**
* Load the mapped file for a namespace prefix and relative class.
*
* @param string $prefix The namespace prefix.
* @param string $relative_class The relative class name.
* @return mixed Boolean false if no mapped file can be loaded, or the
* name of the mapped file that was loaded.
*/
protected function loadMappedFile($prefix, $relative_class)
{
// are there any base directories for this namespace prefix?
if (isset($this->prefixes[$prefix]) === false) {
return false;
}
// look through base directories for this namespace prefix
foreach ($this->prefixes[$prefix] as $base_dir) {
// replace the namespace prefix with the base directory,
// replace namespace separators with directory separators
// in the relative class name, append with .php
$file = $base_dir
. str_replace('\', '/', $relative_class)
. '.php';
// if the mapped file exists, require it
if ($this->requireFile($file)) {
// yes, we're done
return $file;
}
}
// never found it
return false;
}
/**
* If a file exists, require it from the file system.
*
* @param string $file The file to require.
* @return bool True if the file exists, false if not.
*/
protected function requireFile($file)
{
if (file_exists($file)) {
require $file;
return true;
}
return false;
}
}
用法：
我将班级存储在库中，并像常规库一样加载。
$this->load->library('autoloader_psr4');
$this->autoloader_psr4->register();
$this->autoloader_psr4->addNamespace('Noodlehaus', APPPATH . 'third_party/config');
$this->autoloader_psr4->addNamespace('CakeFilesystem', APPPATH . 'third_party/Filesystem');
我有一个项目，我成功使用了Symfony的弃用PSR4CLASSLOADER：https：//github.com/symfony/symfony/class-loader/blob/master/master/psr4classloader.php
如果您需要自动加载psr4样式，则使用此classloader很棒。
作为一个例子：
require_once FCPATH . 'Psr4ClassLoader.php';
$loader = new SymfonyComponentClassLoaderPsr4ClassLoader();
$loader->addPrefix('SkunkbadConsole', FCPATH . 'vendor/skunkbad/console/src');
$loader->register();
在那个示例中，我正在使用控制台类，然后声明名称空间，以及名称空间来自。
的目录位置。$c = new SkunkbadConsoleConsole('ChromePhp');
$c->log([1,2,3,4,5]);
现在我可以加载控制台类，在这种情况下，我将" ChromePhp"作为构造函数参数。然后，我继续在控制台对象上调用日志方法。
在您的情况下，由于命名级的类是phpoffice phpspreadsheet 电子表格，因此您可能会做类似的事情：
require_once __DIR__ . '/path/to/Psr4ClassLoader.php';
$loader = new SymfonyComponentClassLoaderPsr4ClassLoader();
$loader->addPrefix('PhpOfficePhpSpreadsheet', FCPATH . 'vendor/phpoffice/phpspreadsheet/src');
$loader->register();
然后使用它：
$x = new PhpOfficePhpSpreadsheetSpreadsheet();
请理解，我不知道与您的电子表格课程合作的细节，但是我向您展示了如何在没有作曲家的情况下使用它。您可能不得不走到包裹的路径，也许是命名空间本身。