谷歌地图API:使用javascript和html接受相同半径的搜索地址



我想要实现的是接受半径相同的客户端地址,如果地址的半径不同,它应该验证("地址不接受"(或者它不应该工作。

  1. 当客户端或用户输入半径内相同地址的地址时,它应该验证("已接受"(

  2. 当客户端或用户输入的地址在半径内与地址不同时,它应该验证("不接受"(

以下是我尝试执行的代码:-

<html>
<title></title>
<head></head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script type="text/javascript" src="https://www.google.com/jsapi"></script>
<script type="text/javascript">
google.load("maps", "3",{other_params:"key="});
</script>
<script type="text/javascript">
var map = null;
var radius_circle;
var markers_on_map = [];
var geocoder;
var infowindow;
//all_locations is just a sample, you will probably load those from database
var all_locations = [
{type: "Restaurant", name: "Restaurant 1", lat: 40.723080, lng: -73.984340},
{type: "School", name: "School 1", lat: 40.724705, lng: -73.986611},
{type: "School", name: "School 2", lat: 40.724165, lng: -73.983883},
{type: "Restaurant", name: "Restaurant 2", lat: 40.721819, lng: -73.991358},
{type: "School", name: "School 3", lat: 40.732056, lng: -73.998683}
];
//initialize map on document ready
$(document).ready(function(){
var latlng = new google.maps.LatLng(40.723080, -73.984340); //you can use any location as center 
on map startup
var myOptions = {
zoom: 1,
center: latlng,
mapTypeControl: true,
mapTypeControlOptions: {style: google.maps.MapTypeControlStyle.DROPDOWN_MENU},
navigationControl: true,
mapTypeId: google.maps.MapTypeId.ROADMAP
};
map = new google.maps.Map(document.getElementById("map_canvas"), myOptions);
geocoder = new google.maps.Geocoder();
google.maps.event.addListener(map, 'click', function(){
if(infowindow){
infowindow.setMap(null);
infowindow = null;
}
});
});
function showCloseLocations() {
var i;
var radius_km = $('#radius_km').val();
var address = $('#address').val();
//remove all radii and markers from map before displaying new ones
if (radius_circle) {
radius_circle.setMap(null);
radius_circle = null;
}
for (i = 0; i < markers_on_map.length; i++) {
if (markers_on_map[i]) {
markers_on_map[i].setMap(null);
markers_on_map[i] = null;
}
}
if (geocoder) {
geocoder.geocode({'address': address}, function (results, status) {
if (status == google.maps.GeocoderStatus.OK) {
if (status != google.maps.GeocoderStatus.ZERO_RESULTS) {
var address_lat_lng = results[0].geometry.location;
radius_circle = new google.maps.Circle({
center: address_lat_lng,
radius: radius_km * 1000,
clickable: false,
map: map
});
if (radius_circle) map.fitBounds(radius_circle.getBounds());
for (var j = 0; j < all_locations.length; j++) {
(function (location) {
var marker_lat_lng = new google.maps.LatLng(location.lat, location.lng);
var distance_from_location = google.maps.geometry.spherical.computeDistanceBetween(address_lat_lng, marker_lat_lng); //distance in meters between your location and the marker
if (distance_from_location <= radius_km * 1000) {
var new_marker = new google.maps.Marker({
position: marker_lat_lng,
map: map,
title: location.name
});                                     google.maps.event.addListener(new_marker, 'click', function () {
if(infowindow){
infowindow.setMap(null);
infowindow = null;
}
infowindow = new google.maps.InfoWindow(
{ content: '<div style="color:red">'+location.name +'</div>' + " is " + distance_from_location + " meters from my location",
size: new google.maps.Size(150,50),
pixelOffset: new google.maps.Size(0, -30)
, position: marker_lat_lng, map: map});
});
markers_on_map.push(new_marker);
}
})(all_locations[j]);
}
} else {
alert("No results found while geocoding!");
}
} else {
alert("Geocode was not successful: " + status);
}
});
}
}
</script>
<body style="margin:0px; padding:0px;" >
<input id="address" value="Second Steet, New York" placeholder="Input Address"/>
<select id="radius_km">
<option value=1>1km</option>
<option value=2>2km</option>
<option value=5>5km</option>
<option value=30>30km</option>
</select>
<button onClick="showCloseLocations()">Show Locations In Radius</button>
<div id="map_canvas"  style="width:500px; height:300px;">
</body>
</html>

尝试将showCloseLocations函数替换为以下内容:

function showCloseLocations() {
var i;
var radius_km = $('#radius_km').val();
var address = $('#address').val();
for (i = 0; i < markers_on_map.length; i++) {
if (markers_on_map[i]) {
markers_on_map[i].setMap(null);
markers_on_map[i] = null;
}
}
if (geocoder) {
geocoder.geocode({ 'address': address }, function(results, status) {
if (status == google.maps.GeocoderStatus.OK) {
if (status != google.maps.GeocoderStatus.ZERO_RESULTS) {
var address_lat_lng = results[0].geometry.location;
if (radius_circle) {
radius_circle.setRadius(radius_km * 100);
}
else {
radius_circle = new google.maps.Circle({
center: address_lat_lng,
radius: radius_km * 1000,
clickable: false,
map: map
});
}
if (!radius_circle.getBounds().contains(address_lat_lng)) {
alert("This address is outside radius.");
return;
}
if (radius_circle) map.fitBounds(radius_circle.getBounds());
for (var j = 0; j < all_locations.length; j++) {
(function(location) {
var marker_lat_lng = new google.maps.LatLng(location.lat, location.lng);
var distance_from_location = google.maps.geometry.spherical.computeDistanceBetween(address_lat_lng, marker_lat_lng); //distance in meters between your location and the marker
if (distance_from_location <= radius_km * 1000) {
var new_marker = new google.maps.Marker({
position: marker_lat_lng,
map: map,
title: location.name
});
google.maps.event.addListener(new_marker, 'click', function() {
if (infowindow) {
infowindow.setMap(null);
infowindow = null;
}
infowindow = new google.maps.InfoWindow({
content: '<div style="color:red">' + location.name + '</div>' + " is " + distance_from_location + " meters from my location",
size: new google.maps.Size(150, 50),
pixelOffset: new google.maps.Size(0, -30),
position: marker_lat_lng,
map: map
});
});
markers_on_map.push(new_marker);
}
})(all_locations[j]);
}
}
else {
alert("No results found while geocoding!");
}
}
else {
alert("Geocode was not successful: " + status);
}
});
}
}

上面的代码使用LatLngBounds.contains来验证输入地址的LatLng是否在圆的边界内。因此,任何超出"Second Steet, New York"给定半径的地址都将被视为无效。

希望这是你想要的行为。如果没有,请告诉我,以便我可以相应地修改我的答案。

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