c -跳表- 8086组件

Question

我试过这样做:

 switch (si)
{
 case 1:
   printf( “Number One” );
   break;
case 2:
   printf( “Number Two” );
   break;
 case 3:
   printf( “Number Three” );
   break;
 case 4:
  printf( “Number Four” );
  break;
 }

在带有分支表/跳转表的汇编8086中:

enter code here
org 100h 
mov si,1 
mov bx,10
sub si,1
add si,si
mov bx,[bx+si]
jmp bx 
address:
dw 14 Case1
dw 17 Case2
dw 21 Case3
dw 24 Case4 
Case1: PRINTN "Number One"
jmp End
Case2: PRINTN "Number Two"   
jmp End
Case3: PRINTN "Number Three"
jmp End
Case4: PRINTN "Number Four"
End:
mov ah, 0
int 16h
ret

PRINTN类似于c中的printf。

我的代码不工作，我不知道为什么…

我做错了什么?

Answer 1

使用表和for存储字符串的示例:

表本身的地址= OFFSET JTab

JTab dw OFFSET Case1, OFFSET Case2, OFFSET Case3, OFFSET Case4

OFFSET为T1, T2, T3, T4，长度为len1, len2，…的字符串的地址

T1 db "Number One"
len1 = ($-T1)
T2 db "Number Two"
len2 = ($-T2)
T3 db "Number Three"
len3 = ($-T3)
T4 db "Number Four"
len4 = ($-T4)