我正在使用Apache + mod_lua对一个简单的"输出"过滤器进行原型设计。如何通过 LUA 读取应用的其他本机输出筛选器末尾的响应正文?例如,我能否获得将发送给客户端的实际响应?
该手册对此有一些很好的指导:
http://httpd.apache.org/docs/current/mod/mod_lua.html#modifying_buckets
使用 Lua 过滤器修改内容 过滤器功能通过 LuaInputFilter 或 LuaOutputFilter 设计为三级 使用协程挂起和恢复 函数,因为存储桶沿过滤器链向下发送。核心结构 这样的函数是:
function filter(r)
-- Our first yield is to signal that we are ready to receive buckets.
-- Before this yield, we can set up our environment, check for conditions,
-- and, if we deem it necessary, decline filtering a request alltogether:
if something_bad then
return -- This would skip this filter.
end
-- Regardless of whether we have data to prepend, a yield MUST be called here.
-- Note that only output filters can prepend data. Input filters must use the
-- final stage to append data to the content.
coroutine.yield([optional header to be prepended to the content])
-- After we have yielded, buckets will be sent to us, one by one, and we can
-- do whatever we want with them and then pass on the result.
-- Buckets are stored in the global variable 'bucket', so we create a loop
-- that checks if 'bucket' is not nil:
while bucket ~= nil do
local output = mangle(bucket) -- Do some stuff to the content
coroutine.yield(output) -- Return our new content to the filter chain
end
-- Once the buckets are gone, 'bucket' is set to nil, which will exit the
-- loop and land us here. Anything extra we want to append to the content
-- can be done by doing a final yield here. Both input and output filters
-- can append data to the content in this phase.
coroutine.yield([optional footer to be appended to the content])
end