每当我尝试使用一种方法时都会出错

Question

我正在尝试制作一个简单的python脚本来欺骗我的朋友认为get会感染病毒，除非他写下密码p3nis47，但是每当我尝试运行它时，我都会在第17，4和9行出现错误。 17 和 4 只是方法，我不知道为什么我会收到错误，在 9 时我只是减去 1 以确保我只给我的朋友3 尝试输入"密码"。对不起，如果这真的很明显，我刚刚开始学习 python。

count = 4
def ask():
    answer = input("do you wan't a virus ")
    respond(answer)
def respond(response):
    if(response == "p3nis47"):
        print("congrats!!! you don't have a virus")
    else:
        count = count - 1
        if(count == 0):
            print("trololololololololololol")
        print(answer,"is not a vailid answer")
        print("you have ",count," attempts remaining")
        ask()
ask()

Answer 1

使用错误的输入运行程序会产生错误

Traceback (most recent call last):
  File "c.py", line 15, in <module>
    ask()
  File "c.py", line 4, in ask
    respond(answer)
  File "c.py", line 9, in respond
    count = count - 1
UnboundLocalError: local variable 'count' referenced before assignment

这是因为您使用的是全局变量，但您需要让 python 知道它。将global count添加到函数的开头。然后还有另一个错误

Traceback (most recent call last):
  File "c.py", line 16, in <module>
    ask()
  File "c.py", line 4, in ask
    respond(answer)
  File "c.py", line 13, in respond
    print(answer,"is not a vailid answer")
NameError: name 'answer' is not defined

这也很简单。您只是不小心使用了错误的变量名称。有两个更改的工作脚本是

count = 4
def ask():
    answer = input("do you wan't a virus ")
    respond(answer)
def respond(response):
    global count
    if(response == "p3nis47"):
        print("congrats!!! you don't have a virus")
    else:
        count = count - 1
        if(count == 0):
            print("trololololololololololol")
        print(response,"is not a vailid answer")
        print("you have ",count," attempts remaining")
        ask()
ask()

所以，我运行了修复程序...但现在我感染了病毒！