当连续输入错误时，循环会中断 java

Question

当您连续两次输入随机值（例如"i"）时，程序将终止。我希望它，所以"无效数据请重试"，然后是"你想再玩一次"继续重复，直到输入 N 或 Y。

7 8 5
No numbers match
Do you want to play again?
i
Invalid data please try again
Do you want to play again?
i
Thank you for using this program

它应该是：

7 8 5
No numbers match
Do you want to play again?
i
Invalid data please try again
Do you want to play again?
i
Invalid data please try again
Do you want to play again?

。等等。

法典：

import java.util.Random;
import java.util.Scanner;
public class TestSlotMachine {
    public static void main(String[] args) {
        String choice;
        Scanner keyboardScanner = new Scanner(System.in);
        do {
            Random randomNumber = new Random();
            int slot1, slot2, slot3;
            slot1 = randomNumber.nextInt(9);
            slot2 = randomNumber.nextInt(9);
            slot3 = randomNumber.nextInt(9);
            System.out.println(slot1+" "+slot2+" "+ slot3);
            if (slot1 != slot2 && slot1 != slot3 && slot2 != slot3) {
                System.out.println("No numbers match");
            }
            else if (slot1 == slot2 && slot2 == slot3) {
                System.out.println("Three numbers match");
            }
            else {
                System.out.println("Two numbers match");
            }
            System.out.println("Do you want to play again?");
            choice = keyboardScanner.next();
            if (!choice.equalsIgnoreCase("n") && !choice.equalsIgnoreCase("y")) {
                System.out.println("Invalid data please try again");
                System.out.println("Do you want to play again?");
                choice = keyboardScanner.next();
            }
        } while (choice.equalsIgnoreCase("y"));
        System.out.println("Thank you for using this program");
        keyboardScanner.close();
    }
}

Answer 1

if (!choice.equalsIgnoreCase("n") && !choice.equalsIgnoreCase("y"))

可以成为

while (!choice.equalsIgnoreCase("n") && !choice.equalsIgnoreCase("y"))