public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scan = new Scanner(System.in);
int rounds, antonia = 100, david = 100;
int rolla, rolld;
String score;
String[] scorenospace;
System.out.println("How many rounds would you like to play? (1-15)");
rounds = scan.nextInt();
while (rounds > 0) {
score = scan.nextLine();
scorenospace = score.split(" ");
rolla = Integer.parseInt((scorenospace[0]));
rolld = Integer.parseInt((scorenospace[1]));
if (rolla > rolld) {
david = david - rolla;
} else if (rolla < rolld) {
antonia = antonia - rolld;
} else if (rolla == rolld) {
}
rounds--;
}
System.out.println(antonia + david);
}
用户将输入 2 个由空格分隔的数字。我想单独收集和比较作为字符串输入的 2 个数字。我将如何做到这一点?
我的代码抛出越界异常。我很困惑。
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scan = new Scanner(System.in);
int rounds, antonia = 100, david = 100;
int rolla, rolld=0;
String score;
System.out.println("How many rounds would you like to play? (1-15)");
rounds = scan.nextInt();
while (rounds > 0) {
score = scan.nextLine();
rolla = score.charAt(0);
rolld = score.charAt(2);
if (rolla > rolld) {
david = david - rolla;
} else if (rolla < rolld) {
antonia = antonia - rolld;
} else if (rolla == rolld) {
}
rounds--;
}
System.out.println(antonia + david);
}
我也尝试了chatAt方法,但似乎无法使代码正常工作。任何帮助将不胜感激。对于代码质量平庸,我深表歉意。我是编程新手,正在尝试自己尽可能多地学习。非常感谢所有的帮助,干杯:)
如果你想让输入有点像这样,只是一个猜测:
3 12 17 // where 3 is rounds and 12 and 17 are values
23 45 // 23 and 45 again as values
12 36 // 12 and 36 again as values
然后,您可以将代码更改为:
rounds = Integer.parseInt(scan.nextLine());
while (rounds > 0) {
score = scan.nextLine();
rolla = Integer.parseInt(score.split(" ")[0]);
rolld = Integer.parseInt(score.split(" ")[1]);
.
.
.
}
添加另一件事:score.charAt(0( 将为您提供 ascii 等效项。