我使用路径几何组来构建一个几何形状,该几何形状替换WPF中的按钮:
<UserControl.Resources>
<ControlTemplate x:Key="bT" TargetType="Button">
<Path StrokeThickness="1.5" >
<Path.Data>
<GeometryGroup>
<EllipseGeometry Center="7,7" RadiusX="7" RadiusY="7" />
<LineGeometry StartPoint="4,4" EndPoint="10,10" />
<LineGeometry StartPoint="10,4" EndPoint="4,10" />
</GeometryGroup>
</Path.Data>
<Path.Style>
<Style TargetType="{x:Type Path}">
<Style.Triggers>
<Trigger Property="IsMouseOver" Value="False">
<Setter Property="Stroke" Value="LightGray" />
</Trigger>
<Trigger Property="IsMouseOver" Value="True">
<Setter Property="Stroke" Value="Red" />
</Trigger>
</Style.Triggers>
</Style>
</Path.Style>
</Path>
</ControlTemplate>
</UserControl.Resources>
按钮像
一样实现<Button Template="{StaticResource ResourceKey=bT}" />
现在我的问题是我无法以不同的颜色样式。例如,我想要的椭圆地理测定法的行为比我的线域。有没有办法?
您可以在控制图上有几个命名路径,将IsMouseOver
触发器移至ControlTemplate.Triggers
并在设置器中使用TargetName
。还请注意,ControlTemplate中的所有路径都有默认样式。
<ControlTemplate TargetType="Button" x:Key="bT">
<ControlTemplate.Resources>
<Style TargetType="Path">
<Setter Property="Fill" Value="Transparent"/>
<Setter Property="Stroke" Value="LightGray"/>
<Setter Property="StrokeThickness" Value="1.5"/>
</Style>
</ControlTemplate.Resources>
<Canvas>
<Path x:Name="circle">
<Path.Data>
<EllipseGeometry Center="7,7" RadiusX="7" RadiusY="7"/>
</Path.Data>
</Path>
<Path x:Name="cross">
<Path.Data>
<GeometryGroup>
<LineGeometry StartPoint="4,4" EndPoint="10,10"/>
<LineGeometry StartPoint="10,4" EndPoint="4,10"/>
</GeometryGroup>
</Path.Data>
</Path>
</Canvas>
<ControlTemplate.Triggers>
<Trigger Property="IsMouseOver" Value="True">
<Setter TargetName="circle" Property="Stroke" Value="Red"/>
<Setter TargetName="cross" Property="Stroke" Value="Green"/>
</Trigger>
</ControlTemplate.Triggers>
</ControlTemplate>
cross
路径也可以使用路径标记语法简短编写:
<Path x:Name="cross" Data="M4,4 L10,10 M4,10 L10,4"/>