如何操作路径名，使其不会打印出整个名称

Question

我是编程新手。 我需要索引三个单独的 TXT 文件。并从输入进行搜索。当我进行打印时，它会给我整个路径名。我想打印 TXT 文件名。

我尝试在函数中使用 OS.list

import os
import time
import string
import os.path
import sys
word_occurrences= {}
def index_text_file (txt_filename,ind_filename, delimiter_chars=",.;:!?"):
    try:
        txt_fil = open(txt_filename, "r")
        fileString = txt_fil.read()
        for word in fileString.split():
            if word in word_occurrences:
                word_occurrences[word] += 1
            else:#
                word_occurrences [word] = 1
        word_keys = word_occurrences.keys()
        print ("{} unique words found in".format(len(word_keys)),txt_filename)
        word_keys = word_occurrences.keys()
        sorted(word_keys)
    except IOError as ioe: #if the file can't be opened
        sys.stderr.write ("Caught IOError:"+ repr(ioe) + "/n")
        sys.exit (1)
index_text_file("/Users/z007881/Documents/ABooks_search/CODE/booksearch/book3.txt","/Users/z007881/Documents/ABooks_search/CODE/booksearch/book3.idx")

语法

错误：语法无效(base( 8c85908188d1：CODE z007881$ python3 indexed.py9395 在/Users/z007881/Documents/ABooks_search/CODE/booksearch/book3.t 中找到的唯一单词XT

我想说的是 9395 本书中发现的独特单词3.txt

Answer 1

一种方法

是在目录分隔符/上拆分路径并选择最后一个元素：

file_name = txt_filename.split("/")[-1]
# ...
# Then:
print("{} unique words found in".format(len(word_keys)), file_name)
# I would prefer using an fstring, unless your Python version is too old:
print(f"{len(word_keys)} found in {file_name}")

我强烈建议将txt_filename的名称更改为不那么具有误导性的名称，例如 txt_filepath ，因为它不包含文件名，而是包含整个路径(包括但不限于文件名(。