通过JS(超时，TimeInterval)的AutoSubmit表单

Question

我想创建简单的自动提交。例如，如果用户1秒不要在输入中输入任何内容或按Enter键提交。我的代码：

$(document).on('keypress', $('input'), function(e) {
  console.log('clear')
  
  clearInterval(SubmitInterval);
  
  if (e.which == 13) {
    console.log('submit')
  }
  
  var SubmitInterval = setInterval(function() {
    console.log('submit')
    clearInterval(SubmitInterval);
  }, 1000);
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type=text id=1 />

但效果不佳。谢谢

Answer 1

问题是由于您重新定义了每个按键上的SubmitInterval变量。而是在活动处理程序之外声明一次。尝试以下操作：

var submitInterval;
$(document).on('keypress', 'input', function(e) {
  console.log('clear')
  
  clearInterval(submitInterval);
  
  if (e.which == 13) {
    console.log('submit')
  }
  
  submitInterval = setInterval(function() {
    console.log('submit')
    clearInterval(submitInterval);
  }, 1000);
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type=text id=1 />

Answer 2

现在一切都很好。谢谢。

var SubmitInterval;
$(document).on('keypress', $('input'), function(e) {
  clearInterval(SubmitInterval);
  SubmitInterval = setInterval(function () {
    console.log('submit');
    clearInterval(SubmitInterval);
  },1700);
  if(e.which == 13) {
	  console.log('submit');
	  clearInterval(SubmitInterval);
	};
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type=text />