我正在尝试处理有关通道使用和正确处理这些通道的问题(很可能是设计问题)。 我正在使用 Knative 事件/云事件来创建和事件管道。
我希望能够处理不同的通道,以便接收来自不同来源/方法的事件。
为此,我有以下实现(代码已被删除,以便简洁地详细说明问题)。
我有一个file1.go
,它定义了一个EventHandler
结构、关联的方法和几个导出的方法(CreatePreview()
和SaveAndPublish()
),它们是应用程序的"正常"行为,并且实际上接收/处理频道上出现的任何值:
type EventHandler struct {
Channel chan string
}
func (ev *EventHandler) Handle(event cloudevents.Event) {
if event.Data == nil {
(...)
}
var data string
if err := event.DataAs(&data); err != nil {
(...)
}
ev.Channel <- data
defer close(ev.Channel)
}
func (ev *EventHandler) Create(param *Element) (error) {
(...) //Unimportant code
}
func (repo *Repository) CreatePreview(param1 string, param2 string, eventHandler *EventHandler) (*pb.PreviewResponse, error) {
(...)
err := eventHandler.Create(&document)
(...)
preview := <- eventHandler.Channel
(...)
}
func (repo *Repository) SaveAndPublish(param1 string, param2 bool, eventHandler *EventHandler) (*pb.PublishResponse, error) {
(...)
err := eventHandler.Create(&documentToUpdate)
(...)
published := <- eventHandler.Channel
(...)
return repo.SomeOtherMethod(published.ID)
}
现在,在我的main.go
函数上,我有一个服务的"常规"启动,包括一个 gRPC 侦听器、一个 HTTP 侦听器和事件处理。这是通过cmux
完成的。所以这里有一个代码示例(再次,代码简化):
func HandlerWrapper(event cloudevents.Event) {
//TODO: HOW DO I HANDLE THIS???
}
// This approach seems to cause issues since it's always the same instance
// var (
// eventHandler = &rep.EventHandler{Channel: make(chan string)}
// )
func (service *RPCService) Start() (err error) {
port, err := strconv.Atoi(os.Getenv("LISTEN_PORT"))
if err != nil {
log.Fatalf("failed to listen: %v", err)
}
lis, err := net.Listen("tcp", fmt.Sprintf(":%d", port))
if err != nil {
log.Fatalf("failed to listen: %v", err)
}
// Create multiplexer and listener types
mux := cmux.New(lis)
grpcLis := mux.Match(cmux.HTTP2())
httpLis := mux.Match(cmux.HTTP1())
// *************
// gRPC
// *************
service.server = grpc.NewServer()
reflection.Register(service.server)
pb.RegisterStoryServiceServer(service.server, service)
// *************
// HTTP
// *************
// Declare new CloudEvents Receiver
c, err := kncloudevents.NewDefaultClient(httpLis)
if err != nil {
log.Fatal("Failed to create client, ", err)
}
// *************
// Start Listeners
// *************
// start gRPC server
go func() {
if err := service.server.Serve(grpcLis); err != nil {
log.Fatalf("failed to gRPC serve: %s", err)
}
}()
// start HTTP server
go func() {
// With this line bellow, I'd have to create a Received per eventHandler. Not cool
// log.Fatal(c.StartReceiver(context.Background(), eventHandler.Handle))
// Here we use a wrapper to deal with the event handling and have a single listener
log.Fatal(c.StartReceiver(context.Background(), HandlerWrapper))
}()
if err := mux.Serve(); err != nil {
log.Fatalf("failed to Mux serve: %s", err)
}
return
}
//CreatePreview is used to save a preview for a story
func (service *RPCService) CreatePreview(ctx context.Context, input *pb.PreviewRequest) (*pb.PreviewResponse, error){
eventHandler := &rep.EventHandler{Channel: make(chan string)}
story, err := service.repo.CreatePreview("param1", "param2", eventHandler)
if err != nil {
return nil, err
}
// Return matching the `CreatePreviewResponse` message we created in our
// protobuf definition.
return &pb.PreviewResponse{Story: story}, nil
}
// SaveAndPublish is used to save a story and publish it, returning the story saved.
func (service *RPCService) SaveAndPublish(ctx context.Context, input *pb.PublishRequest) (*pb.PublishResponse, error){
eventHandler := &rep.EventHandler{Channel: make(chan string)}
story, err := service.repo.SaveAndPublish("param1", true, eventHandler)
if err != nil {
return nil, err
}
// Return matching the `SaveAndPublishResponse` message we created in our
// protobuf definition.
return &pb.PublishResponse{Story: story}, nil
}
现在,我知道不必实例化单个全局eventHandler
,以便在main.go
c.StartReceiver()
上使用eventHandler.Handle
方法,我可以定义一个包装器,该包装器可能包含 eventHandlers 列表(main.go
上的HandlerWrapper()
方法)。
但是,我不知道如何识别EventHandler
的哪个实例以及如何正确处理和路由这些操作,这就是我的问题:
在这种情况下,我想创建一个包装器(传递给c.StartReceive()
的单个函数),然后让它由正确的Handle()
实例处理?
我希望这个问题是明确的。几天来我一直在尝试解决这个问题,但不知道该怎么做。
据推测,您应该能够通过使用来自该事件的不同源/方法来区分事件。例如,快速浏览一下事件规范,就会发现您可以根据源拆分为多个频道。
我看到这里没有使用的主要内容是上下文对象。似乎你可以从那个上下文中收集来源。这可以在他们的hello world示例中看到(查看接收函数)。
对于您的示例:
// these are all the handlers for the different sources.
type EventHandlers map[string]CloudEventHandler
var _eventHandlerKey = "cloudEventHandlers"
func HandlerWrapper(ctx context.Context, event cloudevents.Event) {
// Get event source from event context.
src := event.Context.Source
// Then get the appropriate handler for that source (attached to context).
handler := ctx.Value(_eventHandlers).(Values)[src]
// ex: src = "/foo"
handler.SendToChannel(event)
}
func main() {
eventHandlers := make(map[string]CloudEventHandler)
// create all the channels we need, add it to the context.
for _, source := range sourceTypes { // foo bar baz
handler := NewHandler(source)
eventHandlers[source] = handler
}
// start HTTP server
go func() {
// Add the handlers to the context.
context := context.WithValue(context.Background(), _eventHandlerKey, eventHandlers)
log.Fatal(c.StartReceiver(context.Background(), HandlerWrapper))
}
}()
如果有 3 个不同的源要支持,您可以使用工厂模式来实例化这些不同的通道和所有这些实现的接口。
// CloudEventHandler Handles sending cloud events to the proper channel for processing.
type CloudEventHandler interface {
SendToChannel(cloudEvents.Event)
}
type fooHandler struct {channel chan string}
type barHandler struct {channel chan int}
type bazHandler struct {channel chan bool}
func NewHandler(source string) CloudEventHandler {
switch source {
case "/foo":
return &fooHandler{channel: make(chan string, 2)} // buffered channel
case "/bar":
return &barHandler{channel: make(chan int, 2)}
case "/baz":
return &bazHandler{channel: make(chan bool, 2)}
}
}
func (fh *fooHandler) SendToChannel(event CloudEvents.Event) {
var data string
if err := event.DataAs(&data); err != nil {
// (...)
}
go func() {
fh.channel <- data
}()
}
func (bh *barHandler) SendToChannel(event CloudEvents.Event) {
var data int
if err := event.DataAs(&data); err != nil {
// (...)
}
go func() {
bh.channel <- data
}()
}