我对如何迭代和获取NSDictionaries数组(不同类/实体)的值感到困惑。以下是我目前正在做的事情:
1) 构建两个独立的NSDictionary数组(不同的实体)2) 将两个阵列与结合使用
NSMutableArray *combinedArrayofDicts = [[NSMutableArray alloc] initWithObjects: sizesArrayOfDicts, wishListArrayOfDicts , nil];
3) 然后组合归档ArrayofDicts:
NSData *dataToSend = [NSKeyedArchiver archivedDataWithRootObject:combinedArrayofDicts];
4) 通过GameKit 传输
[self.session sendDataToAllPiers:dataToSend withDataMode: GKSendDataReliable error:nil];
5) 我该如何在接收端遍历这个数组?我想通过为每个类获取值,该类由类名键控
以下是通过NSLog(2个大小字典和1个愿望清单字典)的外观
Printing description of receivedArray:
<__NSArrayM 0xbc65eb0>(
<__NSArrayM 0xbc651f0>(
{
classname = Sizes;
displayOrder = 0;
share = 1;
sizeType = Neck;
value = "13" or 33 (cm)";
},
{
classname = Sizes;
displayOrder = 0;
share = 1;
sizeType = Sleeve;
value = "34" or 86 (cm)";
}
)
,
<__NSArrayM 0xbc65e80>(
{
classname = Wishlist;
detail = "";
displayOrder = 0;
imageString = "";
latitude = "30.33216666666667";
link = "http://maps.google.com/maps?q=loc:30.332,-81.41";
longitude = "-81.40949999999999";
name = bass;
share = 1;
store = "";
}
)
)
(lldb)
在我的for循环中,我发布了以下内容:
NSString *value = [dict objectForKey:@"classname"];
并得到一个异常:
*由于未捕获的异常"NSInvalidArgumentException"而终止应用程序,原因:"-[__NSArrayM objectForKey:]:无法识别的选择器发送到实例0xbc651f0'
就在数组中混合对象类型而言,这是否令人反感?
@Will用正确的结构引导我找到答案。。以下是最终答案:
NSArray *receivedArray;
if(receivedArray.count>0){
NSArray *combinedArrayofDicts = [receivedArray objectAtIndex:0];
if(combinedArrayofDicts.count>=2){
NSArray *sizesArray = [receivedArray objectAtIndex:0]; // Reference original received array
for(NSDictionary *sizeDict in sizesArray){
NSLog(@"%@",sizeDict);
}
NSArray *wishListArray = [receivedArray objectAtIndex:1]; // Reference original received array
for(NSDictionary *wishDict in wishListArray){
NSLog(@"%@",wishDict);
}
}
}
要获取所需的字典,请使用以下代码,
假设receivedArray是从游戏中心接收的数组
NSArray *receivedArray; if(receivedArray.count>0){ NSArray *combinedArrayofDicts = [receivedArray objectAtIndex:0]; if(combinedArrayofDicts.count>=2){ NSArray *sizesArray = [combinedArrayofDicts objectAtIndex:0]; for(NSDictionary *sizeDict in sizesArray){ NSLog(@"%@",sizeDict); } NSArray *wishListArray = [combinedArrayofDicts objectAtIndex:1]; for(NSDictionary *wishDict in wishListArray){ NSLog(@"%@",wishDict); } } }
如何迭代和获取NSDictionaries数组的值
正如您所说的,您有一个字典数组的数组,您当前的代码不会检索类名的值。
您的返回值在NSArray
中,而不是在NSDictionary
中
所以你需要做一些类似的事情
NSString *value = [returnArray[0][0] objectForKey:@"classname"];
您可以迭代并获得值,如
for (int i = 0; i < [returnArray count]; i++) {
for (int j = 0; j < [returnArray[i] count]; j++) {
NSDictionary *dict = (NSDictionary*)returnArray[i][j];
NSLog(@"%@ ...",[dict objectForKey:@"classname"]);
}
}
也许你可以试试:
NSString *value = [NSString stringWithFormat:@"%@",[dict objectForKey:@"classname"]];
从你的输出来看,我不认为"尺寸"是一个字符串。