api 控制器返回值对象对象,而在邮递员 api 中给出完美的 otuput



这是我的用户ApiController ..

namespace ShoppingCart.Controllers
{
    public class UserApiController : BaseApiController
    {
        [HttpPost]
        public HttpResponseMessage Login(string username, string password)
        {
            return ToJson(db.usp_validateUser(username, password));
        }
    }
}

这是BaseApiController ....

namespace ShoppingCart.Controllers
{
    [Route("api/UserApi")]
    public class BaseApiController : ApiController
    {
        protected readonly aarshpatelEntities db = new aarshpatelEntities();
        protected HttpResponseMessage ToJson(dynamic obj)
        {
            var response = Request.CreateResponse(HttpStatusCode.OK);
            response.Content = new StringContent(JsonConvert.SerializeObject(obj), Encoding.UTF8, "application/json");
            return response;
        }
    }
}

这是我在角度 2 中的服务...

return this._http.post(apiUrl, model)
            .map((res: Response) => {
                let user = res.json();
                if (user) {
                    sessionStorage.setItem('username', user['UserName']);
                }
                else {
                    alert("Username / Password is incorrect !!");
                }
            })

代码有什么问题?我想不通。

.it 取决于您使用的 Angular 版本。

如果您使用的是HTTPCLIENT..尝试:

return this._http.post<YOURTYPE || any>(apiUrl, model)
            .map((res: Response) => {
                let user = res;
                if (user) {
                    sessionStorage.setItem('username', user['UserName']);
                }
                else {
                    alert("Username / Password is incorrect !!");
                }
            })

如果您使用的是Http提供程序:

return this._http.post<YOURTYPE || any>(apiUrl, model)
                .map((res: Response) => {
                    let user = JSON.Parse(res.json()) 
                    if (user) {
                        sessionStorage.setItem('username', user['UserName']);
                    }
                    else {
                        alert("Username / Password is incorrect !!");
                    }
                })

希望对您有所帮助!

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