如何搜索和删除分隔符文本文件中的模式

Question

我有以下文本:

s:50:"index.php?attachment=$matches[1]&cpage=$matches[2]";s:44:"(term-conditions-for-employers)/trackback/?$";s:35:"index.php?pagename=$matches[1]&tb=1";s:71:"(term-conditions-for-employers)/feed/(feed|rdf|rss|rss2|atom|jobman)/?$";s:47:"index.php?pagename=$matches[1]&feed=$matches[2]";s:66:"(term-conditions-for-employers)/(feed|rdf|rss|rss2|atom|jobman)/?$";s:47:"index.php?pagename=$matches[1]&feed=$matches[2]";s:52:"(term-conditions-for-employers)/page/?([0-9]{1,})/?$";s:48:"index.php?pagename=$matches[1]&paged=$matches[2]";s:59:"(term-conditions-for-employers)/comment-page-([0-9]{1,})/?$";s:48:"index.php?pagename=$matches[1]&cpage=$matches[2]";s:44:"(term-conditions-for-employers)(/[0-9]+)?/?$";s:47:"index.php?pagename=$matches[1]&page=$matches[2]";s:26:"home/attachment/([^/]+)/?$";s:32:"index.php?attachment=$matches[1]";s:36:"home/attachment/([^/]+)/trackback/?$";s:37:"index.php?attachment=$matches[1]&tb=1";s:63:"home/attachment/([^/]+)/feed/(feed|rdf|rss|rss2|atom|jobman)/?$";s:49:"index.php?attachment=$matches[1]&feed=$matches[2]";s:58:"home/attachment/([^/]+)/(feed|rdf|rss|rss2|atom|jobman)/?$";

我要做的是搜索单词jobman并删除找到该单词的整个条目。每个条目的分隔符是分号";"。我需要从Mac OS命令行来做。所以我有grep、fgrep和awk等工具可用。

Answer 1

首先，我们需要从文本中删除什么?

$> grep -o -P "[^;]*jobman[^;]*;" ./text 
s:71:"(term-conditions-for-employers)/feed/(feed|rdf|rss|rss2|atom|jobman)/?$";
s:66:"(term-conditions-for-employers)/(feed|rdf|rss|rss2|atom|jobman)/?$";
s:63:"home/attachment/([^/]+)/feed/(feed|rdf|rss|rss2|atom|jobman)/?$";
s:58:"home/attachment/([^/]+)/(feed|rdf|rss|rss2|atom|jobman)/?$";

如果正确，则

$> sed "s/[^;]*jobman[^;]*;//g" ./text 
s:50:"index.php?attachment=$matches[1]&cpage=$matches[2]";s:44:"(term-conditions-for-employers)/trackback/?$";s:35:"index.php?pagename=$matches[1]&tb=1";s:47:"index.php?pagename=$matches[1]&feed=$matches[2]";s:47:"index.php?pagename=$matches[1]&feed=$matches[2]";s:52:"(term-conditions-for-employers)/page/?([0-9]{1,})/?$";s:48:"index.php?pagename=$matches[1]&paged=$matches[2]";s:59:"(term-conditions-for-employers)/comment-page-([0-9]{1,})/?$";s:48:"index.php?pagename=$matches[1]&cpage=$matches[2]";s:44:"(term-conditions-for-employers)(/[0-9]+)?/?$";s:47:"index.php?pagename=$matches[1]&page=$matches[2]";s:26:"home/attachment/([^/]+)/?$";s:32:"index.php?attachment=$matches[1]";s:36:"home/attachment/([^/]+)/trackback/?$";s:37:"index.php?attachment=$matches[1]&tb=1";s:49:"index.php?attachment=$matches[1]&feed=$matches[2]";

我们在"s/[^;]*jobman[^;]*;//g"中实际做的是搜索[^;]*jobman[^;]*;组符号(任何时候都不是:, jobman, :，;)。然后我们用"。然后对所有文本行进行替换