在PowerShell中创建自定义对象时出错

Question

我试图创建一个自定义对象，但收到错误。有人对如何处理这个问题有想法吗？

$tempObject = New-Object System.Object
Add-Member -inputobject $tempObject -type NoteProperty -name Name -value ""
Add-Member -inputobject $tempObject -type NoteProperty -name account   status -value ""
Add-Member -inputobject $tempObject -type NoteProperty -name OU -value ""
Add-Member -inputobject $tempObject -type NoteProperty -name Last Logon -value ""

Add Member：SecondValue参数对于"类型的成员不是必需的；NoteProperty"；，并且不应该被指定。在添加的成员时不要指定SecondValue参数这种类型。

Answer 1

如果字符串中有空格，请将它们放在引号中（单引号或双引号）：

$tempObject = New-Object System.Object
Add-Member -inputobject $tempObject -type NoteProperty -name Name -value ""
Add-Member -inputobject $tempObject -type NoteProperty -name 'account   status' -value ""
Add-Member -inputobject $tempObject -type NoteProperty -name OU -value ""
Add-Member -inputobject $tempObject -type NoteProperty -name 'Last Logon' -value ""

---

更新

根据@wannabeprogrammer在下面的评论，实现上述目标的一种简单方法是：

$tempObject2 = [PSCustomObject]@{ 
    Name = "" ; 
    'Account Status' = "" ; 
    OU = "" ; 
    'Last Logon' = "" 
}

或者获得完全相同（即，使得两种方法中的compare-object在正在创建的对象之间没有差异）。

$tempObject3 = New-Object -TypeName PSObject -Property @{ 
    Name = "" ; 
    'Account Status' = "" ; 
    OU = "" ; 
    'Last Logon' = "" 
}

看看我运行上面的片段是什么意思，然后是下面的：

compare-object $tempObject $tempObject2
compare-object $tempObject $tempObject3
compare-object $tempObject2 $tempObject3