我正在尝试创建一个财政代码计算器算法。
代码如下:
#include<stdio.h>
#include<string.h>
int main()
{
int Day,Month,Year,i;
char Mo;
char Name[1][30];
char Surname[1][30];
char A,B,C,D,E,H,L,M,P,R,S,T;
printf("Insert your birthday day: ");
scanf("%d",&Day);
printf("Insert your birthday month: ");
scanf("%d",&Month);
printf("Insert your birthday year (last two numbers): ");
scanf("%d",&Year);
/*Month calculator*/
switch(Month)
{
case 1:
Mo="A";
break;
case 2:
Mo="B";
break;
case 3:
Mo="C";
break;
case 4:
Mo="D";
break;
case 5:
Mo="E";
break;
case 6:
Mo="H";
break;
case 7:
Mo="L";
break;
case 8:
Mo="M";
break;
case 9:
Mo="P";
break;
case 10:
Mo="R";
break;
case 11:
Mo="S";
break;
case 12:
Mo="T";
break;
}
printf("Your fiscal code is: %d%c%d",Year,Mo,Day);
}
在开关的每种情况下,我都收到相同的错误:指向整数转换的指针不兼容,从"char[2]"分配给"char"。
错误在哪里?
谢谢大家!
您正在尝试将 char
s 分配给char*
s。 Mo
是一个char
,用双引号("
)括起来的字符串char*
以