使用循环通过批处理脚本重命名文件名

Question

我有一个包含文件的文件夹：File1.txt和File2.txt

file1.txt 的内容是：

"DTS053C0 RUN DATE 10/01/11 DATATRAK SYSTEM PAGE 001
RUN TIME 13:35:08
INPUT PROGRAM TRANSMISSION STATUS REPORT
STATUS - INPUT RECEIVED BY DTCC'S DATATRAK SYSTEM
DETAIL RECORDS RECEIVED 0
HEADER RECORD RECEIVED
HDR.SSYSID.E00.CORIG.SSUBOMMDDYYYY HEADERFILEDESCRIPTION N001 *
REJECTED
NO MATCH ON EXPECTED MASTER FOR HEADER" 

file2.txt的内容是：

"The confirm file received from DTCC will be in the following format:
DTS053C0 RUN DATE 10/01/11 DATATRAK SYSTEM PAGE 001
RUN TIME 12:53:32
INPUT PROGRAM TRANSMISSION STATUS REPORT
STATUS - INPUT RECEIVED BY DTCC'S DATATRAK SYSTEM
DETAIL RECORDS RECEIVED 22
HEADER RECORD RECEIVED
HDR.SSYSID.E00.CORIG.SSUBOMMDDYYYY HEADERFILEDESCRIPTION N001 *
ACCEPTED
Example"

我正在寻找一个批处理脚本来分别扫描这两个文件的内容，并识别包含"拒绝"一词的文件，然后向我的电子邮件ID发送电子邮件，例如通知说"此文件已被拒绝，请检查"。

• 我正在使用 blat 发送电子邮件作为通知 *

Answer 1

将@Stephans建议包装成批处理：

• Findstr /M仅报告与REJECTED匹配的文件名，
• for /f处理此输出，集合将其收集在 变量找到。第一个条目生成前导逗号。
• 当最终将此变量内容作为参数传递给子例程时 ：Blat 这个第一个逗号被子字符串从第二个逗号中删除%Found:~1%POS(从零开始(
• 在 sub 中，您可以使用%*=(所有传递的参数(将其作为 blat 例程的邮件主题或正文。

---

:: Q:Test2018614SO_50858355.cmd
@Echo off & Setlocal EnableDelayedExpansion
Set "Search=REJECTED"
Set "Files=file?.txt"
Set "Found="
for /f "delims=" %%A in ('
findstr /m /i "%Search%" %Files%
') Do set "Found=!Found!,%%A"
If Defined Found (
Call :Blat %Found:~1%
) Else (
Echo No files "%Files%" containing "%Search%" found
)
Pause
Goto :Eof
:Blat
Echo found Rejected in %1
If "%2" neq "" (shift & goto :Blat)

示例输出：

> SO_50858355.cmd
Yourblatcommand found Rejected in file1.txt

新示例输出：

> SO_50858355.cmd
found Rejected in file3.txt
found Rejected in file1.txt

批处理文件仅在当前文件夹中搜索，并带有通配符file?.txt因此您必须调整变量以满足您的需求或首先设置工作目录。